Part E At absolute zero, all of the free electrons in the metal have energies less than or equal to the Fermi energy, so N(EF) = Ntotal. Using this equality, you can solve for the Fermi energy Ep and find EF 32/34/32 (Notal 2/3 = 2m The term Ntotal/Vis called the free-electron density and is usually denoted π. (Be sure not to confuse this number with the function (E).) The free-electron density for gold is 5.90 x 1028/m³. What is the Fermi energy EFgold of gold? Express your answer in electron volts to three significant figures. ΜΕ ΑΣΦ Ergold w ? eV

Part E At absolute zero, all of the free electrons in the metal have energies less than or equal to the Fermi energy, so N(EF) = Ntotal. Using this equality, you can solve for the Fermi energy Ep and find EF 32/34/32 (Notal 2/3 = 2m The term Ntotal/Vis called the free-electron density and is usually denoted π. (Be sure not to confuse this number with the function (E).) The free-electron density for gold is 5.90 x 1028/m³. What is the Fermi energy EFgold of gold? Express your answer in electron volts to three significant figures. ΜΕ ΑΣΦ Ergold w ? eV