percentage yield for this reaction when 0.436 mol potassium tetrachloroplatinate was reacted with 0.436 mol ammonia to give 54.2 g Pt(NH3)2Cl2.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 68QRT: Cisplatin, Pt(NH3)2Cl2, a drug used in the treatment of cancer, can be made by the reaction of...
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Cisplatin [Pt(NH3)2Cl2], a compound used in cancer treatment, is prepared by a reaction of ammonia with potassium tetrachloroplatinate: K2PtCl4 (aq) + 2NH3 (g)  2KCl (aq) + Pt(NH3)2Cl2 (s) i. A chemist reacts 0.326 mol of potassium tetrachloroplatinate with 0.436 mol of ammonia. Identify the limiting reagent for this reaction. ii. Calculate the theoretical yield of Pt(NH3)2Cl2 for the reaction above. iii. Calculate the percentage yield for this reaction when 0.436 mol potassium tetrachloroplatinate was reacted with 0.436 mol ammonia to give 54.2 g Pt(NH3)2Cl2.

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