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Photoelectron spectroscopy applies the principle of the photoelectric effect to study orbital energies of atoms and molecules. High-energy radiation (usually UV or x-ray) is absorbed by a sample and an electron is ejected. The orbital energy can be calculated from the known energy of the radiation and the measured energy of the electron lost. The following energy differences were determined for several electron transitions: AE2+1 = 4.098 × 10-17 J AE5-1 = 5.242 × 10-¹7 J AE3-1 = 4.854 × 10-¹7 J AE4-2 = 1.024 × 10-¹7 J Calculate AE and λ of a photon emitted in the following transitions: (a) level 3 → 2; (b) level 4 → 1; (c) level 5 4.

Photoelectron spectroscopy applies the principle of the photoelectric effect to study orbital energies of atoms and molecules. High-energy radiation (usually UV or x-ray) is absorbed by a sample and an electron is ejected. The orbital energy can be calculated from the known energy of the radiation and the measured energy of the electron lost. The following energy differences were determined for several electron transitions: AE2+1 = 4.098 × 10-17 J AE5-1 = 5.242 × 10-¹7 J AE3-1 = 4.854 × 10-¹7 J AE4-2 = 1.024 × 10-¹7 J Calculate AE and λ of a photon emitted in the following transitions: (a) level 3 → 2; (b) level 4 → 1; (c) level 5 4.

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter6: The Periodic Table And Atomic Structure
Section: Chapter Questions
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Photoelectron spectroscopy applies the principle of the photoelectric effect to study orbital energies of atoms and molecules. High-energy radiation (usually UV or x-ray) is absorbed by a sample and an electron is ejected. The orbital energy can be calculated from the known energy of the radiation and the measured energy of the electron lost. The following energy differences were determined for several electron transitions: ΔΕ2–1 : 4.098 × 10-¹7 J AE5-1 = 5.242 × 10-¹7 J ΔΕ3-1 - = 4.854 × 10-17 J AE4-2= 1.024 × 10-¹7 J Calculate AE and λ of a photon emitted in the following transitions: (a) level 3 → 2; (b) level 4 → 1; (c) level 5 → 4.
Transcribed Image Text:Photoelectron spectroscopy applies the principle of the photoelectric effect to study orbital energies of atoms and molecules. High-energy radiation (usually UV or x-ray) is absorbed by a sample and an electron is ejected. The orbital energy can be calculated from the known energy of the radiation and the measured energy of the electron lost. The following energy differences were determined for several electron transitions: ΔΕ2–1 : 4.098 × 10-¹7 J AE5-1 = 5.242 × 10-¹7 J ΔΕ3-1 - = 4.854 × 10-17 J AE4-2= 1.024 × 10-¹7 J Calculate AE and λ of a photon emitted in the following transitions: (a) level 3 → 2; (b) level 4 → 1; (c) level 5 → 4.
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