Please predict the outcome of each reaction below:Type you answer as a letter: A, B, ...., or F. Please predict the outcome of each reaction below:Type you answer as a letter: A, B, ..., or F.Problem 1: https://doi.org/10.1021/ol101705jAnswer to Problem 1:Hint 1. Assume the reaction can ONLY occur at the MOST ELECTRON RICH double bond.Hint 2. Assume the reaction can ONLY occur from the least sterically hindered side of the molecule. Draw or build a 3-dimentional conformation to support your answer.1 equivalentm-CPBA?AHBCDEF

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Answered: Please predict the outcome of each…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter19: Eas: Electrophilic Aromatic Substitution

Section: Chapter Questions

Problem 10E

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They are Sn1 and Sn2 reactions Answer step by step with explanation Please answer correct i will give you upvote.
Draw a curved arrow mechanism for the substitution reaction that will occur with the alkyl halide and nucleophile below, adding steps as necessary. Be sure to include all nonbonding electrons and all nonzero formal charges, and show all species that react or are formed in this reaction. Cl H₂O
Copy the given reaction and show the mechanism by supplying the appropriate curved arrows. Also, identify the general type of reaction mechanism (polar or non-polar). For polar reaction mechanisms, label the nucleophile and the electrophile. :0: :0 O.. H. HÖ: Hö:
In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 See Periodic Table O See Hint :ö: :Br: Add the missing curved arrow notation. 20 F CI Br I Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Keg > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e. Keg « 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg« 1) because bromide is a better leaving group than acetate.
ited Draw both resonance structures of the most stable carbocation intermediate in the reaction shown. od m... • You do not have to consider stereochemistry. . Do not include anionic counter-ions, e.g., I', in your answer. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom Separate resonance structures using the → symbol from the drop-down menu. ● CH4 + ? HBr
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3) Use the reaction shown below and the associated reaction energy diagram to answer the following questions. E A Но- + Br HO. Br- reaction coordinate a) In the space above, use curved arrows to show the mechanism of the reaction. b) Classify the reaction as either addition, elimination or substitution. c) In this reaction is hydroxide (HO-) acting as a nucleophile or as a base? c) Based on the reaction energy diagram, is the reaction endergonic or exergonic? d) Based on the reaction energy diagram, and assuming the reaction is reversible, would the equilibrium lie to the left or to the right? e) Which position on the reaction energy diagram (A, B or C) corresponds to the transition state?
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027 In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 4 See Periodic Table O See Hint :0: :Br: Add the missing curved arrow notation. S CI Br Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Kea > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e., Keq« 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg 1) because bromide is a better leaving group than acetate. +
For the reaction given below, draw a mechanism (curved arrows) and then predict which side of the reaction is favoured under equilibrium conditions. Include lone pairs and formal charges. Predict which side of the reaction is favored under equilibrium conditions, and explain your choice. a. the reactants are favored, because the negative charge on the electronegative oxygen atom is more stable (making it the stronger base). b. the products are favored, because the negative charge on the electronegative oxygen atom is more stable (making it the weaker base). c. the products are favored, because the negative charge on the large sulfur atom is more stable (making it the weaker base). d. the reactants are favored, because the negative charge on the large sulfur atom is more stable (making it the stronger base).

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