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- If you perform a Chi-Squared analysis and determine that your result is greater than the critical value, what would you do? a. Reject H0, accept HA b. Accept H0 c. neithercan you help me answer these 1-4 questions? please thank you! 1. how do you compare product rule from the sum rule of probabilities? 2. What is the importance of sample size and choice of test organism in studies involving probabilities? 3. Differentiate mean, variance, and standard deviation. 4. What does a relatively small standard deviation indicate?When a 95% confidence interval is calculated there is a 95% probability that the next measurement will fall within this range. there is a 95% probability that the true value is within this range. there no chance of having false positives within that range. 1) 1, 2, & 3 2) 2 only 3) 2 & 3 4) 1 only 5) 1 & 2
- In a recently published case control study, the researcher reported an odds ratio of 3.55 (95% CI 1.88-5.4). This indicates that the OR is significant and the associated p=value is less than 0.05. A. TrueB. False please explain the reasoning behind the answer, thank you!Which set of symbols represents high reliability? A B C A and CExplain why CVAR should always be larger than the corresponding VAR VaR = Value at risk
- >> Remaining Time: 25 minutes, 51 seconds. * Question Completion Status: L Unce started, this test must be completed in one sitting. Do not le Your answers are saved automatically. 20 Question 4 O 4 5 6 7 8 A Moving to another question will save this response. 9 Which example does not directly support the good gene hypothesis? peacocks with larger eyespots have babies with higher survival rates female (peahens) prefer male (peacocks) with long tail feathers a male peacock with more of eye spots has larger babies peacocks with more ornaments on their tails were less likely to be eaten by a fox 10 11 12 13 A Moving to another question will save this response.A study published in the journal PLoS One (https://doi.org/10.1371/journal.pone.0217796) in 2019 presented results of a GWAS searching for loci impacting the risk of prolonged QRS in Hispanic/Latino people living in the U.S. QRS prolongation has been associated heart failure and cardiovascular mortality. The Manhattan plot below summarizes the results. The significance threshold for this study is shown as a horizontal line at -log₁0(p-value) ~7.5. The names of candidate genes at each associated locus are shown at the top of the corresponding SNP tower. How many loci containing at least one gene affecting prolonged QRS risk were identified? (d)oT301- 10- 8 0 1 SCN5A-SCN10A HAND1 CDKN1A VTI1A 8 9 10 11 SYT1 MYOCD : 12 13 14 15 16 17 18 19 20 2122 X YA study published in the journal PLoS One (https://doi.org/10.1371/journal.pone.0217796) in 2019 presented results of a GWAS searching for loci impacting the risk of prolonged QRS in Hispanic/Latino people living in the U.S. QRS prolongation has been associated heart failure and cardiovascular mortality. The Manhattan plot below summarizes the results. The significance threshold for this study is shown as a horizontal line at -log₁0 (p-value) ~7.5. The names of candidate genes at each associated locus are shown at the top of the corresponding SNP tower. How many loci containing at least one gene affecting prolonged QRS risk were identified? 10 06 5 7 O 8 i SCNSA-SCN10A CDKN1A HAND1 • 88 : 7 8 9 VTI1A 10 11 SYT1 MYOCD LE 12 13 14 15 16 17 18 19 20 2122 X Y
- Please Answer with reason: 3) The nurse is explaining the inheritance of Huntington disease (autosomal dominant) to a newly diagnosed patient whose partner does not have the gene mutation. Which statement should the nurse make regarding family planning? a. There is a 100% chance with each pregnancy that the child will inherit the gene for Huntington disease. c. There is a 50% chance with each pregnancy that the child will inherit the gene for Huntington disease b. There is a 25% chance with each pregnancy that the child will inherit the gene for Huntington disease d. There is a 0% chance with each pregnancy that the child will inherit the gene for Huntington disease.II.. Interpret and identify what statistical test will be use (parametric or nonparametric) and discuss. 1. Tests of Normality (8 Kolmogorov-Smirnov Sig. Shapiro-Wilk Sex Statistic df Statistic df Sig. SEI Male .052 140 .200 .980 140 .035 Female .062 203 .058 .988 203 .082 *. This is a lower bound of the true significance. a. Lilliefors Significance CorrectionE- Question 1/18 NEXT A BOOKMARK Previous Scenario 1: A man and woman have decided to have children but are worried about possible genetic diseases. The couple visits a geneticist to determine what the possible risks are for their future children. The couple discovers that the mom is a carrier, or heterozygous with the diabetes allele and the dad is homozygous dominant, so neither of them have the disease but the mom has one recessive allele. In order to have Diabetes, you have to have two recessive alleles. The following year, the parents are blessed with a bouncing baby boy! What is the correct genotype of the mom? Aa AA aa