Problem 4:An electron travels with speed 1.0 × 107 m/sec between the two parallel charged platesshown in the figure below. The plates are separated by 1.0 cm and are charged by a 200 Vbattery. Thus, the magnitude of the electric field between the plates is E = 20000 V/m and itpoints in the downwards direction. What magnetic field strength and direction will allow theelectron to pass between the plates without being deflected? Recall that the electric force isFe = qĒ. Answer: B = -(0.002 T) or B = 0.002 T into the page.+++++ + + + + +1.0 cm

Magnitude of magnetic field is 0.002 T and it is directed into the page.Explanation:

Answered: Problem 4: An electron travels with…

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter11: Magnetic Forces And Fields

Section: Chapter Questions

Problem 63AP: An electron of kinetic energy 2000 eV passes between parallel plates that are 1.0 an apart and kept...

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Can a constant magnetic field set into motion an electron initially at test? Explain your answer.
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A proton is fired with a speed of 1.1 ×106m/s through the parallel-plate capacitor shown in the figure(Figure 1). The capacitor's electric field is E⃗ =( 1.0 ×105V/m,down). a. What is the strength of the magnetic field B⃗ that must be applied to allow the proton to pass through the capacitor with no change in speed or direction? b. What is the magnetic field strength in the proton's reference frame? c. What is the electric field strength in the proton's reference frame?
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