Problem 4: Notice the pattern in the above 3 problems. What do you think the distance in micrometers per ocular unit at 1000x would be? Problem 5: It was found that the units on the ocular micrometer and the units on the stage micrometer matched up 40 units to 1.0 mm at 100 power. (So 40 ocular units equals 1.0 mm.) If the wing of a dead fruit fly was measured to be 2.5 ocular micrometer units at a magnification of 100, what is the length of the wing in mm? What does mm stand for?
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- Problem 1: At a total magnification of 100x, a student measures 16.4 ocular micrometer divisions per millimeter. What is the distance, in micrometers, per ocular unit at 100x? Problem 2: At a total magnification of 400x, a student measures 4.1 ocular micrometer divisions per millimeter. What is the distance, in micrometers, per ocular unit at 400x? Problem 3: Notice the pattern in the above 2 problems. What do you think the distance in micrometers per ocular unit at 1000x would be?Question:- We are using in class 4.5 mm and 40X. a) How big is a specimen that takes up 1/2 the field view at 90X?Practice problems: Do on folder paper. 1. You are observing a cell; total magnification 100X. It looks like about 7 cells will fit across the field of view's diameter. How large is this cell? Explain. 2. For the 2nd specimen, you are using a total magnification of 400X. It's harder to estimate this time, so you approximated that 12 cells would fit across the radius. Explain how you would find out the size of one cell.
- Procedure 1 Magnification Light is refracted through two lenses to obtain magnification-the ocular lens and the objective lens. Magnifi- cation of the ocular lens is usually 10x.This means that if you were to view a slide with only the ocular lens, the image would be magnified 10 times. Magnification of the objective lenses varies, but typically is 4× for low power, 10× for medium power, and 40× for high power. (To verify that this is the case for your microscope, look at the side of the objective lens, which usually is labeled with its magnification.) Remember that oil immersion provides even greater magnification at 100×. When calculating the total magnification, you must multiply the magnification of the ocular lens (10) by the power of the objective lens. Fill in Table 3.1 to determine total magnification at each of the different objective lenses on your microscope. Remember that the magnification of the objective lens is usually printed on the side of the lens itself. ABLE 3.1…Problem 4: The human eye can be approximated by a two-lens optical system. Light enters the eye and first travels through the cornea. The cornea has a fixed focal length of 4.16666 cm. Next, light travels through the center of the crystalline lens which has a focal length that can change. For healthy eyes, the crystalline lens is set 0.50000 cm behind the cornea and can vary in focal length from 9.0000 cm to 16.5000 cm. The retina acts as an image screen upon which real images are focused for processing by the brain. The retina is 3.0000 cm behind the crystalline lens. a) Draw a simple diagram of cornea, crystalline lens, and retina for this model eye. b) A person focuses a clear image of an object when the crystalline lens has a focal length of 16.000 cm. Use the fact that the final image lands on the retina to calculate the location of the real object in front of this eye. c) Calculate the total magnification of the two-lens system for the situation in part b). d) Your retina…Question 5 What is the total magnification of a sample with an ocular lens power of 15X and using a 40X objective lens?
- Question: Assume two Silver/Silver-Chloride electrodes are interfacing with human tissue using the Direct contact and Gel-filled contact approaches. In one paragraph, describe which method is the better technique to reduce motion artifacts and explain why.compute for the callibration factor in micrometers of the ocular micrometer using the low power objective. explain your answerMATERIAL METHOD RESULT SUMMARY Lecia DCM3D confocal Microscope 1) Straumann (Straumann AG, Waldenburg, Switzer- land) 2.2mm in diameter (for short, A) (2) Nobel Biocare (Nobel Biocare AB, Goteborg, Sweden) 2.0mm in diameter (for short, B) Xive Implant System (Friadent GmbH, Mannheim, Germany) 2.0mm in diameter (for short, C) (4) Global D (French) 2.5mm in diameter (for short, D) (5) Sweden & Martina (Padova, Italy) 2.5mm in diameter (for short, E) The microstructural parameters used by the discriminatory analysis revealed many differences between the five manufactures in terms of roughness of the drilling surface. Marenzi et al (2018) have considered that Surface micromorphology, which affects the contact between the drill and bone, has been shown to contribute to heat, wear, and corrosion phenomena due to material abrasion and corrosion resistance through several surface texture indicators Can be seen as a factor. Not only the design, but also the…
- Show all work including equations. Patient is treated AP/PA parallel-opposed fields. The fields are set up isocentrically on a 6 MV Linac, The patient's AP/PA separation is 25cm, and the field size at midplane is 14 x 26 cm (W x L). Calculate the AP field size on the skin.What is the diameter of the field of view (DFV) of a 1000x objective lens if the DFV of a 400x objective lens is 500 μ? Express your answer in mm.Tighnari is doing preliminary protein studies on redcrest, a vibrant crimson fruit found in the hot deserts of Sumeru. He extracted proteins in the given sample using phosphate buffer. The resulting crude protein extract was subjected to gel filtration chromatography and SDS-PAGE. GFC results: - Absorbance Peak A B Figure 1. Elution profiles of the mixture of protein standards (black) and crude protein extract (blue). Table 1. Components of the calibration mixture and their corresponding molecular weight. U خلفة X A Elution Volume, mL Identity B Bovine Serum Albumin B-lactoglobulinn Horse Myoglobin Crude Protein Extract Molecular Weight, Da 66000 36800 17600