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- The ionization of benzoic acid is represented by this equation. If a 0.045M solution of benzoic acid has an [H3O+] = 1.7*10-3 at equilibrium, what is the Ka of benzoic acid? A) 1.5E4 B) 6.7E-5 C) 7.7E-5 D) 8.4E-1 E) 3.8E-2Which of the following statements is/are true? (Select all that apply) OThe higher the concentration of OH in a solution, the lower the pH. OThe higher the concentration of OH in a solution, the lower the pOH. O An acidic solution has a pH of geater than 7. The concentration of H30* in pure water is 1.00 x 107 M. OA Bronsted acid is a proton donor in an acid-base reaction.Write the net ionic equation for the acid-base hydrolysis equilibrium that is established when potassium cyanide is dissolved in water. Ac + H20(t) This solution is 16. Submit Answer Retry Entire Group 9 more group attempts remaining red Pred 3rec Visited 2red 2red 2red 2red 5 at (Previous Next Save and Exit nment Cengage Learning | Cengage Technical Support O Focus MacBook Air DII DD 80 888 F8 F9 F6 F7 F3 F4 F5 F1 F2 ! @ 2$ & 4 7 1 Q W E R T Y U. K * 00
- Practice Questions: 1) You have an unknown weak acid HA at a concentration of 5% (v/v), a density of 1.05 g/mL, and a molar mass of 60. a. Convert the %(v/v) to molarity. b. Fill in the following ICE Table: [HA] [H*] [A'] Initial Your answer to la Change Equilibrium 0.00397 c. Calculate HA's Ka. What acid is it? d. What is the %-ionization of HA?9. The base ionization constant K, describes which of the following reactions for a weak base, B, in aqueous solution? (а) в + н' BH B+ H,0° BH + H,0 (с) в -но ВН + ОН (d) в + он ВН + ОН (е) в -но BH + 0Evolution Chemisty 를 Op II 17. I Ch. I An S Sol 101 b Ans Co Lab Email Searches G The Sol Titi i app.101edu.co Apps School SWGOH MSF SWTOR Amazon Noodle Bills Possible Purchases Reading list Question 14 of 35 Submit Which one of the following correctly shows the equilibrium for the weak base quinoline, CoH,N? A) CH-N (aq) + 2 H2O (1I) = C»H;NHz* (aq) + 2 Он (ад) B) CH-N (aq) + H2O (I) = CoH;NH+ (aq) + OH- (aq) C) CH-N (aq) + H2O = CH&N (aq) + H3O- (aq) D) CH-N (aq) + H2O (I) = C»H&NO (aq) + H3O+ (aq) +
- 4. Determine the pOH of each solution. (a) [H3O*] = 1.2 × 10-8 M (b) [H3O*] = 5.5 × 10-2 M (c) [H3O*] = 3.9 × 10-9 M (d) [OH¯] = 1.88 × 10-13 MHELPPP QUESTIONNSSSS THABKSKSKS 1) if a solution has a pH of 3.8 what is the pOH ? 2) what is the pOH of a solution that has [OH-] =6.3 x 10^-6 ? 3) what is the [H+] for a solution with a pH of 5.2 ? 4) what is the [OH-] for a solution with a pOH of 9 ? 5) What is the [H+] for a solution that has a [OH-]=2.2x 10^-6? ***********always round the tenths place (1 decimal place ) Thank youWhich of the following 0.10 M acid solutions is expected to have a lower pH than 0.10 M CHBr₂COOH? (Select all that apply.) Structure of CHBr₂COOH [] n n [] Br Br :0 th Br Br CI -C Br -ő- H J16-Ō o=0: CI [4. the -H Br th H C H o=0: :0=0 0=0: o=0: :0: :0: 44 H the H H -Ö-H
- Problem 7. For each of the ff. items, briefly explain the basis of your answer. I. Arrange the following acids according to increasing strength: H,S, PH, HCI. 2. Arrange the following acids according to increasing strength: H,S, H,0, H,Se, H, Te 3. Which compound of each of the following pairs is the stronger acid? a) H,PO, or H,AsO, b) H̟BO, or H,CO, 4: Which compound of each of the following pairs is the stronger acid? a) HNO, or HNO, b) HCIO, or HCIO,answer them all asap and ill give a great review Part A Which of the following acids is the weakest? The acid is followed by its K, value. O HBRO, 2.8 x 109 O HNO2, 4.6 x 104 O HF, 6.8 x 104 O CeHsCOOH, 6.5 x 105 O HCIO2, 1.1 x 102 Submit Request Answer Consider the following reaction: Cus Oyla=Cu(s) + SOlg) Areaction mixture initially contains Cus and 2.9MO, Determine the equilbrium concentration of OyK. for the reaction at this temperature is 1.5. O 19M O 12M O 17M O 050 M O 22M How many of the following are weak acids? HBRO2 HCOOH HNO3 H2PO4 O 3 O 4 O 1 O 2 Submit Request AnswerBased on the given K, values, rank the following acids from strongest (1) to weakest 2 3. (5). Carbonic acid, K,-4.4x107 8. 6. Oxalic acid, K,-5.4x102 3 v Acetic acid, K-1.8x105 11 12 2. Hydrofluoric acid, H=6.6x104 Hydrocyanic acid, K-6.2x10 10