PROBLEM NO. 2 A fined grained soil (no sand) is found to have a liquid limit of 70%, and a plastic limit of 38%. 70 CH
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- A silt clay soil has a plastic limit of 25 and a plasticity index of 30. 70 CH 60 CL U-b RI0.73(L 20) MH |-line OL OF CL-ML ML OH or OL 10 16 20 30 $0 60 70 80. Liquid limit 90 100 a. If the natural water content of the soil is 35%, what is the liquidity index? b. What type of soil is this using the USCS. c. What type of soil is this using the AASHTO system?Based on the sieve analysis a soil has % finer for the following sieves: No. 10- 80% ; No. 40- 68% and No. 200- 48%. The liquid limit is 30 and Plasticity index is 11. Classify the soil by AASHT0 classification and give also the group index.a. A-6 (2) b. A-7-5(8)c. A-6 (9) d. A-7-6(8)5 Problem: For a given inorganic soil, the following are known: Percentage passing No. 4 Sieve... 100 Percentage passing No. 200 sieve.. 77 Liquid limit Plasticity index.... ...... 63 25 70 CH or CL U-b RI40.73(L-20) MH -line OL PIOLL- CL-ML OF ML OH or OL 10 16 20 30 40 50 60 70 80 90 100 Liquid limit Classify the soil by using Unified Sqil Classification System. a) What type of soil is this? b) What is the group symbol of the soil C) What is the group name of the soil?
- Based on the sieve analysis a soil has % finer for the following sieves: No. 10- 100% ; No. 40- 78% and No. 200- 82%. The liquid limit is 32 and Plasticity index is 12. Classify the soil by AASHT0 classification and give also the group index. a.A-6 (5) b.A-6 (9) c.A-7-5(8) d.A-7-6(8)• Problem 1- . Classify the soil to be used as a highway subgrade material using AASHTO classification system; Sieve No. No. 4 No. 10 No. 20 No. 40 No. 60 No. 140 No. 200 Size opening (mm) 4.75 2.00 0.850 0.425 0.250 0.140 0.075 % Finer 100 92 84 69 50 40 37 Liquid limit for soil passing # 40 sieve was determine to be 40% and plasticity index was 20%.Based on the sieve analysis a soil has % finer for the following sieves: No. 10- 90% ; No. 40- 74% and No. 200- 58%. The liquid limit is 38 and Plasticity index is 12. Classify the soil by AASHT0 classification and give also the group index. a. A-7-5(8) b. A-6 (5) c. A-6 (9) d. A-7-6(8)
- AASHTO SOIL CLASSIFICATION (by AASHTO) AASHTO = American Association of State Highway and Transport Officials Situation 2 Classification of Highway Subgrade Materials % FINER SOIL B SIEVE General classification Granular materials (35% or less of total sample passing No. 200) SOIL A SOIL C 10 83 100 90 A-1 А-2 Procedure: 40 48 92 76 Group classification A-1-a А-1-b А-3 A-2-4 A-2-5 A-2-6 A-2-7 O Group Classification with required test data in mind, proceed from left to right, in chart. The correct group will be found by process of elimination. The first group from the left consistent with the test data is the corect classification. 86 34 Sieve analysis (percentage passing) No. 10 200 20 LL 20 70 37 50 max. 30 max. No. 40 No. 200 Characteristics of fraction PI 32 18 50 max. 51 min. 15 max. 25 max. 10 max. 35 max. 35 max. 35 max. 35 max. Using AASHT0 method: 1. Determine the group symbol and index for soil A. 2. Determine the group symbol and index for soil B. 3. Determine the group symbol…Soil Mechanics Based on the sieve analysis a soil has % finer for the following sieves: No. 10- 90% ; No. 40- 48% and No. 200- 22%. The liquid limit and Plasticity index is 5. Classify the soil by AASHT0 classification and give also the group index. a. A-2-7(1) b. A-2-6 (0) c. A-3 (0) d. A-1-b(0)Answer ALL Questions Time: 2 Hours Q3: Classify the following soil by using the Unified soil classification system. Give the group symbols and the group names. Table 1. Sample 1 Grain Size Results (ASTM D422). Table 2. Atterberg Limits Results (ASTM D4318). Sleve No. Dia. (mm) % Passing Sample PL LL % in 12.7 100 G0 40 14 4.75 97 #10 2 94 #20 0.85 84 # 40 0.425 57 #60 0.25 32 140 0.106 15 #200 0.075 100 90 Atterberg Limit Results: LL = 60%, PL = 40% E 80 * 70- 60 - 50 40 30- a 20 10 1 30 a40 100 0.1200 10 80 0.01 Particle Diameter (mm) Answer ALL Questions Time: 2 Hours 70 CH or OH 60 A-line PI = 0.73(LL - 20) Or 50 40 30 CL MH OL 20 or CL-ML OH ML 10 - or OL 10 16 20 30 40 50 60 70 80 90 100 Liquid limit Figure 5.3 Plasticity chart Percent (%) Finer by Weight Plasticity index U-line PI = 0.(LL - 8) O Cengage Learning 2014
- For a soil specimen, given the following: % passing sieve #4-92 %, sieve #10 -81%, sieve # 40-78%, LL-48%, PL-16%, GI-18.2 classify the soil by AASHTO classification system. GI = (F200-35)[0.2 + 0.005 (LL - 40)] +0.01 (F20015)(PI – 10)A soil sample is having liquid limit of 60% and plastic limit of 25%. This soil can be classified as A CH B MH Your answer is C MI D CI• Problem 2--- From the following data of the grain size analysis Sieve size #4 #8 #10 #25 #60 #100 # 200 Pan Sieve opening (mm) 4.76 2.36 2.00 0.71 0.25 0.149 0.074 Determine; a) Cu and Cc system % Finer (by weight) 80 56 51 35 18 13 7 ——— b) classify the soil using the unified soil classification