Please answer all parts with part b and c Problem#4A very long-frame grain dryer is built with cross-section of an isosceles triangle with the dimensionsshown below. For solar heating, the right opaque side is exposed to the sun, the left side is insulated. Ata particular time, the conditions for the inside surfaces of the dryer are as shown in the diagram.a. Solve for F31, F13, F21, F12 (using symmetry, reciprocity, and summation)b. What will be the floor temperature T3 (K)?c. What will be the temperature of the insulated wall T₂?For part b and part c, use thermal network resistance method (for radiation).Surface L(m)T(K) q"(W/m2)E154501.02500.62333.5-6000.35

Answered: Problem#4 A very long-frame grain dryer…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Hello, I don't understand how to solve 5-9 in the photo below. Because I can't find the correct elaboration on the solutions, I hope that you can show me how to get to this answer. I have added my own calculations in a photo for your insight. These are the correct answers: T1 max = 2,37 kNm tmaxCD = 35,6 MPa tmaxDE = 23,3 MPa Thanks for your help! Julia
Solve the following problem.
Material 1- BRASS The below shown graph is drawn from the tabulated values of steel which we measured during the experiment of thermal (Diameter = 25mm) conductivity: (Consider the value of heater power (Q') and the area of cross section (A) of the material from the tabulated values) Power X-axis 1 unit =1 cm y-axis 1 unit = 10°C Temperature (°C) 50- Q' 1 2 3 4 5 6 7 8 (W) 14.65 79 77.4 76 50.1 46.5 42.4 36 34.5 : 20- 10- Distance X in cm 123 10 Material 2 - STEEL Calculate the following: Thermal conductivity of (Diameter = 25mm) steel Calculated Value quantities Power Difference in temperature (AT) C° (with sign) Difference in distance Temperature (°C) between test points (Ax) cm Slope from the graph °C/m (with sign) Q' 1 (W) 2 3 7 8 Thermal conductivity of steel ksb W/m°C 14.2 88.6 87.5 85 33.9 33.6 32.4
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Ex.15: Compute the temperature distribution in a rod that is heated at both ends as depicted in the following figure. Use Gauss- Seidel method given that:- T₁+2T₁+T₁_₁ = 0 where T, represents the temperature at any nodal point. Perform your calculation correct to five decimal places, and use (T = 0) as an initial guess. To = -10 °C T₁ x T₂ T3 Ts = 10 °C
Hello, I don't understand how to solve 5-19 in the photo below. Because I can't find the correct elaboration on the solutions, I hope that you can show me how to get to this answer. I have added my own calculations in a photo for your insight. These are the correct answers: tmaxEA= 5,66 MPa tmaxCD = 8,91 MPa Thanks for your help! Julia
Read the question carefully and give me right solution according to the question. Use Superposition method.
Topics Discussed: Static of Rigid Bodies, Force Vector, Addition of a System of Coplanar Forces, Cartesian Vector Please re-compute and re-solve the given, This is my answer. But I also want to see your expert answer if we land in the same solutions and answers. Please show your complete solution. Thank you.
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Find: 3. 4. NOTE: 200 mm ● Submitted responses shall be to 4 significant figures. Do NOT use scientific notation. O Additionally, angles will be reported with 2 decimal places. NOTE: 1. The magnitude of the horizontal component of the reaction force at Support-A is 2. The magnitude of the vertical component of the reaction force at Support-A is The magnitude of the horizontal component of the reaction force at Support-B is The magnitude of the vertical component of the reaction force at Support-B is 5. The magnitude of the horizontal component of the force carried by Pin-C is 6. The magnitude of the vertical component of the force carried by Pin-C is 3 kN For Directions: Hinge 400 mm Use the "standard coordinate system". Measure in the positive direction. Use a number between and including 0°-360°. 12.5 kN/m C 400 mm kN. kN. kN. kN. kN. kN.

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