Propane (C₂H2-2) is burned with atmospheric air. The analysis 6. the products on a dry basis is as follows: CO₂ = 11% 0₂ = 3.4% CO = 2.8% N₂ = 82.8% Calculate the air-fuel ratio and the percent theoretical air and determine the combustion equation.
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- Methane (CH4) is burned with air (79% N2 and 21% O2 by volume) at atmospheric pressure. The molar analysis of the flue gas yields CO, %3D 10.00%, O2 = 2.41%, C0= 0.52%, and N2 = 87.07%. Balance the combustion %3D equation and determine the mass air-fuel ratio, the of stoichiomet- percentage ric air, and the of excess air. percentageIsooctane (C8H18) is burned with air in an engine at an equivalence ratio of 0.83%. Assuming complete combustion. The percent of (H2O) in the products is: 3.29% 11.85% 7.89% 8.88% 4.56% 14.06%s.com/course.html?courseld%3D15828855&HeplD353706194671Of71a192e43597b01c6e0#10301 Principles of Chemistry I (Chem 1107-327) signments <09 - Pre-Lab 9.11 Pre-Lab Methane burns in oxygen to produce CO2 and H2O. CH:(9) + 202(g)→2H»O(1) +CO2(g) Part A If 0.55 L of gaseous CH, is bumed at STP, what volume of O, is required for complete combustion? Hνα ΑΣφ Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining 40 DELL
- A gaseous fuel contains by volume:CO2 = 2.6 % ,CO = 6 %, O2= O.6 % ,N2= 3.66 % ,H2= 48.0%CH4= 34 %, C2H4=5.2 %Calculate the minimum volume of air required for complete combustion of 100 m3 of the gas. If 50 % excess air is supplied, find the volume of each of the dry constituents of the flue gas.2. The orsat analysis of the products of fuel oil C12H26 = combustion yields: CO₂ = 12.5%, 0₂ = 3.5%, CO = 0.2%, N₂ 83.5%. Determine the actual air fuel ratio (kga/kgf) and the excess air.Q: (186g) of Phosphor element react with 213 g of Chloral gas[Cl2] to produce 205.5g of PCI5. Compute the Yield Percent? Mwt. P =31, CI =35.5 glmole. O 78.33% 92.13% O 47.86% O 57.93% 82.19% 63.78% Does Not Exist
- A fuel containing 80% CH4 and 20% C2H6 is burned with dry air. Sixty percent of the carbon burned goes to CO2, the rest going to CO. Fifty percent excess air is used. Calculate the number of moles of each constituents of the wet flue gas produced by combustion of 100 mole of fuel gas, and also the Orsat analysis of the flue gas.The nitrogen content of organic compounds can be determined by the Dumas method.The compound in question is first passed over hot CuO(s): Compound ----> N2(g) + CO2(g) + H2O(g) The gaseous products are then passed through a concentrated aqueous KOH solution to remove the CO2.The remaining gas contains N2 and water vapor.A 0.185-g sample of a compound was treated as above, producing 82.2 mL of N2 saturated with water vapor at 25 °C and 775.0 torr.What is the mass percent of nitrogen in the compound? (The vapor pressure of water at 25 °C is 23.8 torr.)Suppose you have a soil that is made up of 10% organic matter with CEC = 200 cmol/kg, 40% kaolinitewith CEC = 10 cmol/kg, and 50% vermiculite with CEC = 100 cmol/kg.1- Calculate the overall CEC of the soil by taking a weighted average of the three soil components.2- What percentage of the overall CEC is contributed by the organic matter? How does that numbercompare to the 10% of the soil itself that is organic?
- In measurements made in the chimney (stack), the amount of total specific dry stack gas was measured as 11.6 Nm3/kg and the CO2 ratio in the flue gas as 12%. Since 1.47% of the carbon in the fuel is burned as carbon monoxide, what is the carbon (C) ratio in the fuel? a. 75,7% b. 64,6% c. 53,1% d. 60,3%sunflower oil + 3methanol <--> 3 biodiesel product + glycerol A transesterification takes place by using sunflower oil and methanol and 1%wt. NaOH as catalyst. The ratio of sunflower oil to methanol is 1:6. 100g of sunflower oil will be used in this experiment. The result gives 60% glycerol yield. Calculate the mol and gr amount of the glycerol that is used according to these ratios: a) 1:6 b) 1:3 c)1:2What is the mole ratio for O2 gas to water for the balanced equation for the complete combustion of butane. 2C4H10(g)+ 13O2(g)-> 10H2O(g) + 8CO2(g)