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- The encrypted version of a message is "DEZA RWZMLW HLCXTYR." If it was encrypted using the function f(p) : cipher), what was the original message? (p + 11) mod 26 (the CaesarThe Reflection algorithm can be used to encrypt a C-string (character array terminated with the null character) before it is transmitted over the Internet. The Reflection algorithm works as follows: Each letter in the message is converted to the letter in that is 13 positions to the right of that letter in the English alphabet. If the end of the alphabet is reached, counting continues from the first letter in the alphabet. The case of the letters must be maintained. For example,'M' →'Z', 'x' → 'k', 'A' → 'N'The numeric characters ('0' to '9') are shifted 5 positions to the right of that number in the character set '0' to '9'. If ‘9’ is reached, counting continues from ‘0’. For example,'0' → '5', '2' →'7', '8' → '3' All other characters are left as they are. a) What would the following string be encrypted to by the Reflection algorithm?“Call me at 662-2002 Ext 85393” b) Write a function, getPosition, which finds the position of a letter in the alphabet regardless of the case of the…6. In a Rivest, Shamir and Adleman (RSA) cryptosystem, a particular user uses two prime numbers P and Q to generate the public key and the private key. If P is 23 and Q is 29, using RSA algorithm, find the following: e) public key f) private key g) Encrypted data (Assume the original message, M=7) h) Decrypted data
- Experiment 1: IMPLEMENTATION OF CAESAR CIPHER Objective: To implement the simple substitution technique named Caesar cipher using C+ language. Theory: To enerypt a message with a Caesar cipher, each letter in the message is changed using a simple rule: shift by three. Each letter of the message is shifted a fixed distance (3 for example) down the alphabet, A becomes D, B becomes E, and so on. For the last letters, we can think of alphabet as a circle and "wrap around", W becomes Z. X becomes A, Y becomes B, and Z becomes C. To change a message back, cach letter is replaced by the one three before it. Example ABCDEFGHIJKLMNOPQRSTUVWXYZ t t t t t t t t ttt t t t t t t tt t t t t t t ft DEFGHIJKLMNOPQRSTUVW XY Z ABc) digorithm STEP-1: Read the plain text from the user. STEP-2: Read the key value from the user. STEP-3: If the key is positive then encrypt the text by adding the key with each character in the plain text. STEP-4: Else subtract the key from the plain text. STEP-5: Display the…Alice wants to send Bob her account number for his dining dollars. Bob’s account number is 24. Bob wants to encrypt her account number using the RSA algorithm scheme as evil Eve wants to steal her money to buy M&Ms. Bob chooses two prime numbers, 23 and 37, and uses them to compute the number m. Bob then computes the number e and the number d by using things he knows about the number m and its relationship to e. Bob sends the number e and the number m to Alice and she uses them to encrypt her number A and obtains the number C. C is the encrypted version of her code. Alice sends the number C to Bob, and then Bob uses the number d to decrypt Alice’s message. Using this information, encrypt and decrypt the message to show that the RSA algorithm works, then in a few words explain what makes the algorithm secure if the key for encrypting is always public.1. Messages are to be encoded using the RSA method, and the primes chosen are p “ 13 and q “ 23, so that n “ pq “ 299. The encryption exponent is e “ 13. Thus, the public key is p299, 13q. (a) Use the repeated squaring algorithm to find the encrypted form c of the message m “ 84. (b) Show that the decryption exponent d (the private key) is 61. (c) Verify that you obtain the original message after decryption. Use the repeated squaring algorithm. Please no plagiarism and also i want clear had writting. Thanks.
- for letter in encrypt: new_position=(alphabets.find(letter)-key)%len(alphabets) decrypt+=alphabets[new_position] print("Decrypted message:",decrypt) can you explain line by line what each method and function doesBob sent Alice an encrypted message. The message consists of 3 words. In each word, Bob encoded the letters as follows: A = 01, B = 02, C = 03, ., Z = 26. The he wrote the codes next to each other to form a number that represent the word. For example, the word "WE" is encoded as: 2305 since it consists of 2 letters W=23 and E=05. After encoding, Bob encrypted each encoded word with RSA using Alice public key(pq, e) where p=100000007, q=10000019, e=13. Alice received the following 3 encrypted words from Bob: 451095483713115 570203572152011 958266071840609 She used here RSA private key (d) to decrypt the message. The first word of the message that Bob sent was: WE. Q1. What is the private key d? (enter you answer as an éxact number) ord) Q2. What is the second word of the message that Bob sent to Alice? (enter you answer as one Q3. What is the third word of the message that Bob sent to Alice? (enter you answer as one word)Use RSA cryptography with public key p = 11 q = 13 and e = 23 to encrypt your unique student number. You need to remove all the consecutive zeros in the middle of the student number, then divide your student number into the blocks of two-digits from left to right. Afterwards, you will need to encrypt the resulted list of numbers by RSA. For example, the student number 13060009867 becomes the list of [13, 6, 98, 67]. Then you need to directly encrypt the numbers 13, 6 , 98 and 67 by RSA.
- Elliptic Curves: Let E5(0,1) be an elliptic curve defined over Z5. E5(0,1): y2 mod 5=x3+1 mod 5 Assume two people A and B want to exchange a secret key using Elliptic Curve Diffie-Hellman Key Exchange (ECDH) method. Given the two private key nA=3 and nB=2, please calculate the public keys PA and PB and the secret key K. NO SPAM!!! PLEASE SHOW PROCEDURES WITH CORRECT ANSWER!!!Bob sent Alice an encrypted message. The message consists of 3 words. In each word, Bob encoded the letters as follows: A = 01, B = 02, C = 03, ..., Z = 26. The he wrote the codes next to each other to form a number that represent the word. For example, the word "WE" is encoded as: 2305 since it consists of 2 letters W=23 and E=05. After encoding, Bob encrypted each encoded word with RSA using Alice public key(pq, e) where p=100000007, q=10000019, e=13. Alice received the following 3 encrypted words from Bob: 451095483713115 570203572152011 762324289903198 She used here RSA private key (d) to decrypt the message. The first word of the message that Bob sent was: WE.Encryption is commonly used to disguise messages on the internet. A Caesar cipher performs a shift of all of the characters in a string (based on their ASCII values, see Table 2.1), e.g. h e l l o → m j q q tThe example shows a shift with a distance of 5characters, i.e. h(ASCII:104) → m(ASCII:109)Write a C/C++ program that asks the user to input a line of plaintext and the distance value and outputs an encrypted text using a Caesar cipher, with the ASCII values range from 0 through 127. Use underscores (ASCII: 95) to represent space characters.Underscore characters should not be encrypted, and any character that is encrypted may not become an underscore. In this case, the character should be changed to the next character in the ASCII table.The program should work for any printable characters.NB: No strings (datatype) or library functions may be used.See Figure 2.1 for example output.