Q1) a-The electrical conductivity and electron mobility for aluminum are 3.8X10' (2.m)and 0.0012 m/V.s, respectively. Calculate the Hall voltage for an aluminum specimen that is 15 mm thick for a current of 25 A and a magnetic field of 0.6 tesla (imposed in a direction perpendicular to the current). b-An Iron rod of length I and a cross section A has to be replaced by another rod (where the length of the second rod is half of the first and its cross section is one-third of the first). Find the material which has to be used in the second rod to equalize the resistance of the first.
Q1) a-The electrical conductivity and electron mobility for aluminum are 3.8X10' (2.m)and 0.0012 m/V.s, respectively. Calculate the Hall voltage for an aluminum specimen that is 15 mm thick for a current of 25 A and a magnetic field of 0.6 tesla (imposed in a direction perpendicular to the current). b-An Iron rod of length I and a cross section A has to be replaced by another rod (where the length of the second rod is half of the first and its cross section is one-third of the first). Find the material which has to be used in the second rod to equalize the resistance of the first.
Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter12: Electronic Control Devices
Section: Chapter Questions
Problem 14RQ
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