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- The rate of heat flow equation is Q O A. Thermal resistance OB. Thermal coefficient O C. None of these OD. Thermal conductivity Type here to search KA(T₁-T₂) X E The term X ΚΑ is known as 99+The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093sn3 Read and analyze the following questions and answer themvery carefully. Show your complete (show unit cancellation)and step-by-step solution and box your final answer. Use threedecimal places.
- Q2: The accompanying figure shows the graph of a -2 -1 function g(t) domain [-2, 0] and range [-4, 0]. Find the domains and ranges of the function y = g(1) -4 y = -g+2) -1, and sketch their graphs. 20 MarkQ3: Consider evaluation of different temperatures of solar photovoltaic/thermal system (PVT) as shown in Figure 1(a). The following set of differential equations represent energy balance equations to be solve using matrices and eigenvalues using MATLAB: dTglass = -0.75Tgtass + 0.75TpvT (1) dt - 1.187glass – 22Tpyr + 23Twax (2) dt dTwax 12Tglass + 18TpyT – 19 Twax (3) dt Where, Tgtass , TPVT, and Twax, are temperatures illustrated in Figure 1(b). At time t-0 the initial conditions are Tglass = 35 , Tpyr = 33, and Twax = 31 °C. Cold suppty In frem water Tank Glass PVT Espann Nane-PCMPVT Collector Wax Tubes Sterg Tank Nanofluid Heat Exchanger Contalner Tepe Teek oe Pump for drainAn air conditioner supplies cold air at the same temperature to each room on the fourth floor of the building shownin Fig. The floor plan is shown in Fig. The cold air flow produces an equal amount of heat flow ݍ out of each room. Write a set ofdifferential equations governing the temperature in each room, where To= temperature outside the building, Ro= resistance to heatflow through the outer walls, Ri= resistance to heat flow through the inner walls. Thermal capacitance of each room is C. Assumethat (1) all rooms are perfect squares, (2) there is no heat flow through the floors or ceilings, and (3) the temperature in each roomis uniform throughout the room. Take advantage of symmetry to reduce the number of differential equations to three.
- 11. Athermally insulated battery is being discharged at atmospheric pressure and constant volume. During a 1 hour test it is found that a current of 50 A and 2 V flows while the temperature increases from 20°C to 32.5°C. Find the change in internal energy of the cell during the period of operation. [Ans.-36 x 104 J]A fire has been happened near a wall in a building, suppose the heat transfer f(x, y) = y²-K(x² + equation in the wall will be according to the equation: 2x - xy) a- Compute the constant (K) if you know that the heat transfer equation satisfy the following differential equation a²fa²f + = 0 дх2 т дуг b- Find the location of extreme heat value in the wall 4 2.Given a horizontal beam AB with two supports A and B is subjected to an external distributed load w-50N/m, and an external force F-100N as shown in the following figure. F A 77777 XX 1 m 1m a) The force due to distributed load wis 3 m b) The resultant force of the equivalent system is W B 77777 N located m measured from A. N downward located m measured from A. Time lef
- Datos: F1(KN)=5 F2(KN)=20 F3(KN)=10 L1(m)=4 H(m)=-5 I add the picture of the questionQ4/ For the figure below:* a) gFy is: 0 0 0 0 0 0 C O С O-860.12 O 0 0 0 0 0 0 C 0.6m 0.2 F2=1000 N -824.59 С -831.64 -900 -789.22 Q4/b) EFx is: * 0 0 0 0 0 0 0 - 840.88 Other: O-525.146 O-521.46 O -510.2 C -499.54 490.54 -515.32 0 Other: Q4/C) The resultant R is * 977.6 983.57 950.21 945.54 960.24 965.22 400 Other: 0.8m F1=1600N +0.4 4 F3=900 N 3 Q4/d) The resultant direction is 0 0 0 0 0 0 0 0 F4=1200N C 58 60 65 54 50 52 63 Other:E and 5 v X O file:///C:/Users/Hp/Desktop/mm/OUTCOME%20NO.2%20and%205%20with%20Problems.pdf + O Fit to page D Page view A Read aloud 1 Add notes Problems 1. A brass rod of diameter 25 mm and length 250 mm is subjected to a tensile load of 50 kN and the extension of the rod is equal to 0.3 mm. Find the Young's Modulus or Modulus of Elasticity. 99+ to search hp delete prt sc 14 DI backs & 7 8 24 4 P EJR -0 J K H D. F