Question 10 The current estimate of the RTT (round-trip time) is RTTo 5.0 ms and the initial value of the mean deviation (dispersion) Do = 0.7 ms. The further measurements resulted in the following values for RTT: M₁ = 3.8 ms; M₂ = 3.8 ms; M3 = 3.8 ms; M4 = 2.3 ms; M5 = 2.3 ms; M₁ = 5.0 ms; M7 = 10.0 ms. Using the Jacobson algorithm cal- culate the RTO corresponding to each measurement (assume the smoothing factors a = y = 0.875 for calculations of RTT and D, respectively). Explain the impact of the value of the parameter a on evaluation of the RTT.

Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Question 10
The current estimate of the RTT (round-trip time) is RTTo 5.0 ms and the initial
value of the mean deviation (dispersion) Do = 0.7 ms. The further measurements
resulted in the following values for RTT: M₁ = 3.8 ms; M₂ = 3.8 ms; M3 = 3.8 ms; M4
= 2.3 ms; M5 = 2.3 ms; M₁ = 5.0 ms; M7 = 10.0 ms. Using the Jacobson algorithm cal-
culate the RTO corresponding to each measurement (assume the smoothing factors a
= y = 0.875 for calculations of RTT and D, respectively). Explain the impact of the
value of the parameter a on evaluation of the RTT.
Transcribed Image Text:Question 10 The current estimate of the RTT (round-trip time) is RTTo 5.0 ms and the initial value of the mean deviation (dispersion) Do = 0.7 ms. The further measurements resulted in the following values for RTT: M₁ = 3.8 ms; M₂ = 3.8 ms; M3 = 3.8 ms; M4 = 2.3 ms; M5 = 2.3 ms; M₁ = 5.0 ms; M7 = 10.0 ms. Using the Jacobson algorithm cal- culate the RTO corresponding to each measurement (assume the smoothing factors a = y = 0.875 for calculations of RTT and D, respectively). Explain the impact of the value of the parameter a on evaluation of the RTT.
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