R1 Rc Vcc 91601 Rg Ry 0100555 - 987047944 CE g1601 The values of some resistors and source in the circuit are given belo, S5- 9870479441 g160100555 - 987047944/ Rg = 1k g160100 =100k RC = 9k RE = 1k Ry = 10k VCC = 20V g160100555 - 987047944/ For the transistor used in the circuit, hfe = hFE = 160100555-9870479447 According to what is given, 8704 • . | Find IC current b. Find the value of the resistance g160100555 - 987047944 = hoe = 0, VBE = g160100 87047944 10055 D. g160100550687047944 VCE = 10V and C. 9441 Find the input resistance (ri). Find the voltage gain (Kv). 916055 R2, 0100555-987047944 g160 0100555 -987047944 0100555-987047944

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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According to what is given,
RI
Rc
Vcc
g1601
C2
R2.
RE
Ry
0100555-9870479447
CE
g1601
g160100555 - 987047944
160.
Rg = 1k R1 = 100k RC = 9k RE = 1k Ry = 10k VCC = 20V
g160100555 - 9870479447
287047
For the transistor used in the circuit, hfe = hFE =
s160100555-9870479447
g1601005
08704
a.
g160100555- 9870479447
| Find IC current
• b. Find the value of the resistance
= hoe = 0, VBE
10055
D.
Find the input resistance (ri).
Find the voltage gain (Kv).
= 10V and
R2.
100555-987047944/
0100555-987047944
20100555-987047944
916055
916055
916055
Transcribed Image Text:According to what is given, RI Rc Vcc g1601 C2 R2. RE Ry 0100555-9870479447 CE g1601 g160100555 - 987047944 160. Rg = 1k R1 = 100k RC = 9k RE = 1k Ry = 10k VCC = 20V g160100555 - 9870479447 287047 For the transistor used in the circuit, hfe = hFE = s160100555-9870479447 g1601005 08704 a. g160100555- 9870479447 | Find IC current • b. Find the value of the resistance = hoe = 0, VBE 10055 D. Find the input resistance (ri). Find the voltage gain (Kv). = 10V and R2. 100555-987047944/ 0100555-987047944 20100555-987047944 916055 916055 916055
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