Radio station KUTD broadcasts its radio signal at a frequency of 1.08E8 Hz from an antenna tower. The total power broadcast by the antenna is 3.41E7 W. Suppose your car radio is receiving KUTD’s broadcast at a distance of 7.66E3 m from the antenna. If KUTD’s broadcast antenna acts like an ideal point source of radio waves, what is the intensity of the radio signal received by your car (in W/m2)?
Radio station KUTD broadcasts its radio signal at a frequency of 1.08E8 Hz from an antenna tower. The total power broadcast by the antenna is 3.41E7 W. Suppose your car radio is receiving KUTD’s broadcast at a distance of 7.66E3 m from the antenna. If KUTD’s broadcast antenna acts like an ideal point source of radio waves, what is the intensity of the radio signal received by your car (in W/m2)?
Chapter16: Electromagnetic Waves
Section: Chapter Questions
Problem 98AP: A radio station broadcasts its radio waves with a power of 50,000 W. What would be the intensity of...
Related questions
Question
Radio station KUTD broadcasts its radio signal at a frequency of 1.08E8 Hz from an antenna tower. The total power broadcast by the antenna is 3.41E7 W. Suppose your car radio is receiving KUTD’s broadcast at a distance of 7.66E3 m from the antenna. If KUTD’s broadcast antenna acts like an ideal point source of radio waves, what is the intensity of the radio signal received by your car (in W/m2)?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Step 1: In this step we have collected the input data and also formulated the question precisely.
VIEWStep 2: In this step, a formula is provided to compute the intensity of radio signal at your car
VIEWStep 3: Computed the intensity of radio signal at your car using the formula (1).
VIEWSolution
VIEWTrending now
This is a popular solution!
Step by step
Solved in 4 steps with 5 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you