Series capacitors Combinations: 1. Select three resistors and measure their capacitance with the Fluke meter. C1 = 13.8nF C2 = 12.7 nF C3 = 3.38 nF (F: Farad - unit of capacitor; n: Nano- 1x 10-9 2. Using Equation 1 to calculate the equivalent capacitance 3. The measured the equivalent capacitance Ce is 2.34 nF 4. Compare the calculated value with the measured value, show the difference. Difference = calculated value-measured value

Physics for Scientists and Engineers: Foundations and Connections
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Chapter27: Capacitors And Batteries
Section: Chapter Questions
Problem 17PQ: A pair of capacitors with capacitances CA = 3.70 F and CB = 6.40 F are connected in a network. What...
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CAPACITANCE
When capacitors are connected in series, the equivalent capacitor is:
1/Ce=1/C1 + 1/C2 + ... (Equation 1)
When capacitors are connected in parallel, the equivalent capacitor is:
Ce = C1+ C₂+... (Equation 2)
Transcribed Image Text:CAPACITANCE When capacitors are connected in series, the equivalent capacitor is: 1/Ce=1/C1 + 1/C2 + ... (Equation 1) When capacitors are connected in parallel, the equivalent capacitor is: Ce = C1+ C₂+... (Equation 2)
Series capacitors Combinations:
1. Select three resistors and measure their capacitance with the Fluke meter.
C1 = 13.8nF C2 = 12.7 nF
C3 = 3.38 NF
(F: Farad - unit of capacitor; n: Nano- 1x 10-9
2. Using Equation 1 to calculate the equivalent capacitance
3. The measured the equivalent capacitance Ce is 2.34 nF
4. Compare the calculated value with the measured value, show the difference.
Difference = calculated value - measured value
5. Find percent error:
% error = (| calculated value-measured value|/ calculated value) * 100%
Transcribed Image Text:Series capacitors Combinations: 1. Select three resistors and measure their capacitance with the Fluke meter. C1 = 13.8nF C2 = 12.7 nF C3 = 3.38 NF (F: Farad - unit of capacitor; n: Nano- 1x 10-9 2. Using Equation 1 to calculate the equivalent capacitance 3. The measured the equivalent capacitance Ce is 2.34 nF 4. Compare the calculated value with the measured value, show the difference. Difference = calculated value - measured value 5. Find percent error: % error = (| calculated value-measured value|/ calculated value) * 100%
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