Short Answer 5. You identify two recessive mutations in fruit flies, one that results in curly wings (cc) and one that results in an ebony body (ee). You cross two flies that are heterozygous for both traits (CcEe), and find 352 flies progeny in the next generation with the following phenotypes: wild type - 193 wild type body, curly wings - 64 wild type wings, ebony body - 69 curly wings, ebony body - 26 You believe the curly and ebony alleles assort independently and are not linked. Perform a chi square analysis for this cross to test the null hypothesis. A) Show the expected numbers for each phenotype, and the final X value. Observed Expected (0-e)?/e x2 Edit View Insert Format Tools Table

Biology: The Unity and Diversity of Life (MindTap Course List)
14th Edition
ISBN:9781305073951
Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Chapter13: Observing Patterns In Inherited Traits
Section: Chapter Questions
Problem 9GP: In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive...
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Short Answer 5. You identify two recessive mutations in fruit flies, one that results in curly wings (cc) and one that results in an ebony body (ee). You cross two flies that are heterozygous for both traits (CCEE), and find 352 flies progeny in the next generation with the
following phenotypes:
wild type – 193
wild type body, curly wings - 64
wild type wings, ebony body – 69
curly wings, ebony body - 26
You believe the curly and ebony alleles assort independently and are not linked. Perform a chi square analysis for this cross to test the null hypothesis.
A) Show the expected numbers for each phenotype, and the final X value.
Observed Expected (o-e)²/e
Edit View Insert Format Tools Table
Transcribed Image Text:Short Answer 5. You identify two recessive mutations in fruit flies, one that results in curly wings (cc) and one that results in an ebony body (ee). You cross two flies that are heterozygous for both traits (CCEE), and find 352 flies progeny in the next generation with the following phenotypes: wild type – 193 wild type body, curly wings - 64 wild type wings, ebony body – 69 curly wings, ebony body - 26 You believe the curly and ebony alleles assort independently and are not linked. Perform a chi square analysis for this cross to test the null hypothesis. A) Show the expected numbers for each phenotype, and the final X value. Observed Expected (o-e)²/e Edit View Insert Format Tools Table
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