Show the content of cach of the stack s and the queue q after the below code is execution: Content of s: Stack s = new Stack(); Queue q - new Queue (); s.push (5); s.push (9); s.push (3); s.push (s.top () + 2); while (!s.isEmpty ()) { if (s.top () % 3 0) Content of q: q. enqueue (s.top() + 2); s.pop (); else s.pop ();
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- The Deque ADT combines characteristics of the Stack and the Queue. The name “Deque" comes from "double-ended queue" and is usually pronounced "deck". Like the Stack and the Queue, a Deque permits elements to be accessed only at the ends. However, a Deque allows items to be added at either end and removed from either end. We can refer to the operations supported by the Deque as enqueueFront, enqueueRear, dequeueFront, and dequeueRear. Note that once you have a Deque, you can use it to implement both the Stack and the Queue. Implement the Deque using a dynamic, linked implementation (15pts) Use your Deque to implement a Stack (15pts). Use your Deque to implement a Queue (15pts). Test your implementation across the 3 data structures to tell the story of your work (10pts).The school cafeteria offers circular and square sandwiches at lunch break, referred to by numbers 0 and 1 respectively. All students stand in a queue. Each student either prefers square or circular sandwiches. The number of sandwiches in the cafeteria is equal to the number of students. The sandwiches are placed in a stack. At each step: If the student at the front of the queue prefers the sandwich on the top of the stack, they will take it and leave the queue. Otherwise, they will leave it and go to the queue's end. This continues until none of the queue students want to take the top sandwich and are thus unable to eat. You are given two integer arrays students and sandwiches where sandwiches[i] is the type of the ith sandwich in the stack (i = 0 is the top of the stack) and students[j] is the preference of the jth student in the initial queue (j = 0 is the front of the queue). Return the number of students that are unable to eat. use the following code to complete:-…Given the following stack A = {29,18,10,15,20,9,5,13,2,4,15) Create a queue by taking the elements from the top of the stack and adding them to the queue.
- Note : addqueue works like Enqueue and deleteQueue works like Dequeue Consider the following statements: (8, 9) queueType queue; int num; Show what is output by the following segment of code num = 7; queue.addQueue (6); queue.addQueue (num); num = queue.front (); queue.deleteQueue(); queue.addQueue (num + 5); queue.addQueue (14); queue.addQueue (num queue.addQueue (25); queue.deleteQueue (); 2); cout <« "Queue elements: "; while (!queue.isEmptyQueue ()) { cout <« queue.front () << " "; queue.deleteQueue(); } cout <« endl; Queue elements: 14 14 4 25 Queue elements: 11 14 4 4 Queue elements: 11 14 4 25 Queue elements: 11 14 25 2513. If a stack is implemented under a Single- LinkedList, how much time does a stack pop an item out and maintain the top information? а. О(1) b. O(n) с. 0(n?) d. 0(log n)In linked list implementation of a queue, the important condition for a queue to be empty is? a) FRONT is null b) REAR is null c) LINK is empty d) FRONT == REAR-1
- Consider the following code segment , The variable q is an object of type Queue, the variable s is an object of type Stack. peek method looks at the first element in the queue without removing it. the remove method removes the first element from the queue. add method adds an element to the and of the queue or add an element to the top of the stack. pop method removes an element from the top of the stack What would be the content of the variable q (8 numbers) after we complete the second while loop in the code for (int i = 30; i <= 40; i ++) { if(i % 3 == 0) q.add(i); } while (!q.isEmpty()) { s.add(q.peek()); s.add(q.peek()); q.remove(); } while (!s.isEmpty()) { q.add(s.pop()); }Your job is to implement a Stack using only a Queue(s). That is, you will be responsible for writing the push and pop methods for a Stack but your internal data representation must be a Queue: void push(Queue& queue, int element) int pop(Queue& queue)What does the following function do?void mystery(queueType<int>& q){stackType<int> s;while (!q.isEmptyQueue()){s.push(q.front());q.deleteQueue();}while (!s.isEmptyStack()){q.addQueue(2 * s.top());s.pop();}}
- For example: Programming generates and modifies linked lists: Typically, the software monitors two nodes: How to utilise the null reference in the node of a linked list in two common scenarios.void stack::do(){ for(int i=0li<=topindex/2;i++){ T temp=entry[i]; entry[i]=entry[topindex-i-1]; entry[topindex-1-i]=temp;} } Assume the stack is array based. What is this method do? a. swap the first item with last item b. doesn't do any thing c. replace each item with next item value d. reverse the stackQueues and stacks can be implemented by using linked list structure. To implement "pop" and "push" methods of stack, ... and .. methods of linked list can be used, respectively. To implement "enqueue" and "dequeue" methods of queue, .. and. methods of linked list can be used, respectively. Fill in the blank with correct answers. O pop_front - push_back - pop_back - push_back O pop_back - push_front - pop_front - push_front pop_back - push_back - pop_front - push_back O push_back - pop_back - push_back - pop_front