Similar to the previous one but with some slight changes, what will the following piece of code print? my_age = 18 if my_age >= 18: print("You are responsible for your own acts") elif my_age <= 18: print("You are still underage") elif my_age == 18: print("Happy birthday!") Select one: a. O b. "Your are still underage" c. "You are responsible for your own acts" O d. "Happy birthday!" "You are responsible for your own acts" "Your are still underage" "Happy birthday!"
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- Welcome Assignment ### welcome_assignment_answers ### Input - All eight questions given in the assignment. ### Output - The right answer for the specific question. def welcome_assignment_answers(question): # The student doesn't have to follow the skeleton for this assignment. # Another way to implement it is using "case" statements similar to C. if question == "Are encoding and encryption the same? - Yes/No": answer = "The student should type the answer here" elif question == "Is it possible to decrypt a message without a key? - Yes/No": answer = "The student should type the answer here" return (answer) # Complete all the questions. if __name__ == "__main__": # use this space to debug and verify that the program works debug_question = "Are encoding and encryption the same? - Yes/No" print(welcome_assignment_answers(debug_question)) As you can see, the first two questions are already in the skeleton code. Please follow the first two questions…Full Code: #include#include#include #define seed 5457 #define max(a,b) \({ __typeof__ (a) _a = (a); \__typeof__ (b) _b = (b); \_a > _b ? _a : _b; }) #define min(a,b) \({ __typeof__ (a) _a = (a); \__typeof__ (b) _b = (b); \_a < _b ? _a : _b; }) int initializeArray(int [], const int);void randperm(int b[], int n);int checkboard(int b[], int n);void displayboard(int b[], int n);double factorial(double n); int main(){srandom(seed);int mini[21], maxi[21];double meani[21], sizei[21], sizei_f[21];int n;for (n=4; n<=20; n++){int b[n];initializeArray(b,n);printf("~~~~~~~~~PRINTING FOR %d~~~~~~~~~~~~~\n",n); int total = 0;int x;for (x = 0; x<10; x++){int count = 1;randperm(b,n);while(!checkboard(b,n)){randperm(b,n); count++;}if (x==0){mini[n] = count;maxi[n] = count;displayboard(b,n);}mini[n] = min(mini[n],count);maxi[n] = max(maxi[n], count);total += count;}meani[n] = total/10.0f;double size = pow(n,n);sizei[n] = size;double size_f = factorial(n);sizei_f[n] = size_f;…def division_calculator(a, b): ''' Question 4 You are asked to write a small division calculator, where you are taking 'a' as dividend and 'b' as the divider. You will need to return both the quotient and the remainder. Your returned result should be the: "a is divided by b, with the quotient equals 'quotient' and remainder equals 'remainder'" Note: You must use f-string to do this question. Args: a (int), b (int) Returns: string >>> division_calculator(3, 1) "3 is divided by 1, with the quotient equals 3 and remainder equals 0." ''' # print(division_calculator(9, 3))
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- Payment = Principal [rate ((1 + rate)months)] [(rate + 1)months - 1] For the formula to compute monthly payment, see Listing 2.9, ComputeLoan.java. (Financial application: loan amortization schedule) The monthly payment for a given loan pays the principal and the interest. The monthly interest is computed by multiplying the monthly interest rate and the balance (the remaining princi- pal). The principal paid for the month is therefore the monthly payment minus the monthly interest. Write a program that lets the user enter the loan amountText-based adventure game: Pretend you are creating a text-based adventure game. At different points in the game, you want the user to select to fight, run, or hide from certain enemies. Modify the application below (week3.py) so that the selection variable is sent as an argument into the choice() function. The user should enter 1 to fight, 2 to run, or 3 to hide in the main(). The choice() function should print one of the three options. You will need to add an if statement in the choice() function to make the correct selection.In Germany, the house number is displayed after the street name; for example, Bahnhofstraße 1. Change the print_address function from this section so that it can print addresses in either format. address.cpp 1 #include 2 #include 3 using namespace std; 4 5 struct StreetAddress 6 { 7 8 9 }; 10 11 void print_address (StreetAddress address, bool number_first) 12 { 13 14 } Tester.cpp 1 #include 2 #include 4 5 6 { 7 8 9 10 int house_number; string street_name; using namespace std; PARTNE56 struct StreetAddress }; 19 11 void print_address (StreetAddress address, bool number_first); 12 13 int main() 14 { int house number; string street_name; 15 16 white_house.house_number = 1600; 17 white_house.street_name = "Pennsylvania Avenue"; 18 StreetAddress white_house; CodeCheck print_address (white_house, true); cout << endl<<< "Expected: 1600 Pennsylvania Avenue" << endl; 20 StreetAddress train station; train station. house number = 1; train station.street_name = "Bahnhofstraße"; 21 22 23…
- This is what i have for this code but a lot is worng and i dont know why # Step 1:beatles = []print("Step 1:", beatles) # Step 2:beatles = ["John Lennon", "Paul McCartney", "George Harrison"]print("Step 2:", beatles) # Step 3:new_members = []new_members = ["Stu Sutcliffe", "Pete Best"beatles.append(new_members)print("Step 3:", beatles), # Step 4:beatles.remove("Stu Sutcliffe")beatles.pop(1)print("Step 4:", beatles) # step 5beatles.insert(0, 'Ringo Starr')print("Step 5:", beatles)print("The Fab", len(beatles))Bulgarian solitaire def bulgarian_solitaire(piles, k): You are given a row of piles of pebbles, all identical, and a positive integer k so that the total number of pebbles in these piles equals k*(k+1)//2, the arithmetic sum formula that equals the sum of positive integers from 1 to k. Almost as if intended as a metaphor for the bleak daily life behind the Iron Curtain, all pebbles are identical and you don't have any choice in your moves. Each move picks up one pebble from each pile (even if doing so makes that pile vanish), and creates a new pile from the resulting handful. For example, starting with[7, 4, 2, 1, 1], the first move turns this into [6, 3, 1, 5]. The next move turns that into [5, 2, 4, 4], which then turns into the five-pile configuration [4, 1, 3, 3, 4], and so on. This function should count how many moves are needed to convert the given initial piles into the goal state where each number from 1 to k appears as the size of exactly one pile, and return that count. These…Credit Card Number Check. The last digit of a credit card number is the check digit, which protects against transcription errors such as an error in a single digit or switching two digits. The following method is used to verify actual credit card numbers but, for simplicity, we will describe it for numbers with 8 digits instead of 16:• Starting from the rightmost digit, form the sum of every other digit. For example, if thecredit card number is 4358 9795, then you form the sum 5 + 7 + 8 + 3 = 23.• Double each of the digits that were not included in the preceding step. Add all digits ofthe resulting numbers. For example, with the number given above, doubling the digits,starting with the next-to-last one, yields 18 18 10 8. Adding all digits in these valuesyields 1 + 8 + 1 + 8 + 1 + 0 + 8 = 27.• Add the sums of the two preceding steps. If the last digit of the result is 0, the number isvalid. In our case, 23 + 27 = 50, so the number is valid.Write a program that implements this…