SOLVE STEP BY STEP IN DIGITAL FORMAT 6. For the circuit in the figure, determine: a) The total impedance in polar form. b) The current c) The voltages VR, VL and Vc d) Impedance diagram e) The power supplied.
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- Given the system below, for a unit step input, determine the percentage overshoot **I need a step by step answer please :)١-The PMSM used in the industry due to: a- Their low noise. b- Their easy control arrangement. c- Their efficiency. 2- The BLDCM used in the industry due a- Their low noise. b- Their easy control arrangement. - Their efficiency. 3- The (PMSM) supplied by: a- DC voltage. b- AC voltage of sinusoidal waveform. C- AC voltage of trapezoidal waveform. Choicesa) Determine the sources of harmonics produce in a provided power system circuit shown in Figure 6. S Primary AC Source Transformer Secondary Figure 6 AC/DC Full-wave Rectifier Capaictor HE www Non- linear Load b) Explain how harmonic are formed through different sources, which you have identified in above power system circuit and analyse the effects of harmonic through logical development of principles. c) Analyse different methods of harmonics mitigation to eliminate the harmonic, which you have identify in above power system circuit. You can use harmonic filters, K or equivalent transformers or oversized neutral method depending upon the harmonic sources.
- Q2. For the circuit shown in figure (a), let the frequency is 1KHZ, and V1 = 20Vms, draw the following: 100uF C2 V1 1000UF R1 VSINE 2K A. Impedance diagram B. Voltages phasor diagram. C. Measure the voltage across R1, Vin, and the capacitors, C1, C2 us ng the oscillscope using PROTEUS software. D. Measure the current in the circuit using DMM E. From the above measurments verify your result.B. Coupling capacitors and Bypass capacitors. What are these capacitors? Where to be used in the amplifier circuits? Why to use these capacitors? i BI -Do the following: a.)Convert 0.7692*10-9 Hz into Mrad/s b.)Convert 22*10-9 Hz into Grad/s
- Reconsider Problem 3.29. If Va,VbandVc are a negative-sequence set, how would the voltage and current relationships change? (a) If C1 is the complex positive-sequence voltage gain in Problem 3.29 and (b) if C2 is the negative sequence complex voltage gain, express the relationship between C1andC2Q1. following: For the circuit shown in figure (a). Let V1 = 10Vms, frequency 10KHZ. Draw the A. Impedance diagram. B. Voltages phasor diagram. C. Current phasor diagram. D. Measure the voltage across R1,R2, Vin, and the inductor using the ocillscope using PROTEUS software. E. Measure the voltage in R1, R2, and the inductor using DMMby using PROTEUS software. F. From the above measurments verify your result. R2 1K V1 VSINE R1 L1 2K 1000MRefer to the figure below in which surge protectors p and q are used to protect an expensive high-definition television. If there is a surge in the voltage, the surge protector reduces it to a safe level. Assume that each surge protector has a 0.94 probability of working correctly when a voltage surge occurs. Complete parts (a) through (c) below. TV Series Configuration Parallal Configuration a lf the two surge protectors are arranged in series, what is the probability that a voltage surge will not damage the television? Do not round.) b. If the two surge protectors are arranged in parallel, what is the probability that a voltage surge will not damage the television? (Do not round.) c. Which arrangement should be used for better protection? O The series arrangment provides better protection because it has a higher probability of protection. O The parallel arangment provides better protection because it has a lower probability of protection. O The series arrangment provides better…
- Take a look at the attached screenshot. Then, write down in words you guess as to what would happen to the circuit if the below were to be adjusted. a) Frequencyb) Amplitudec) DC Offsetd) Time per DivisionWhich one is correct? A variable capacitor bank may be required to improve power factor, depending on the load. Power factor correction always results in a power factor greater than 0.9. Power factor correction has an impact on active power flow on the system .(i.e. MW value) A capacitor bank is always going to improve the power factor.Since R1=18.10Kohm, R2=67.58Kohm, RC= 1.08Kohm, RE= 3.23Kohm, VCC=14.00V, Beta=241.00 in the circuit given in the figure, calculate the IC current by doing a complete analysis. When performing your operations, 2 steps will be taken after the point. choose the closest one from the stylish ones according to the +/-10% margin of error. There is only 1 correct answer to the question.