Solve the following initial-value problem: y'+ (tan x)y=cos²x; y(0) = − 1 Oy=2(cos.x)(sin.x+1)-3 O y=(cosx)(sin .x−1) Oy= (sin x) (cos.x - 1) - 1 Oy=(sin x) (sin .x - 1) - cos x

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