Solved Problem: Larry has a mass of 80 kg and runs across the front of the classroom with a speed of 4 m/s and jumps onto d The skateboard is initially at rest and a mass equal to Larry's. If friction with the floor is negligible, what is the speed of Larry and the skateboard after he jumps on board? Known: m = 80 kg, v, 4 m/s, m, = 80 kg, v = 0 m/s, Find the speed of Larry and the skateboard after the "collision." Principle: Momentum is conserved in an inelastic collision.
Solved Problem: Larry has a mass of 80 kg and runs across the front of the classroom with a speed of 4 m/s and jumps onto d The skateboard is initially at rest and a mass equal to Larry's. If friction with the floor is negligible, what is the speed of Larry and the skateboard after he jumps on board? Known: m = 80 kg, v, 4 m/s, m, = 80 kg, v = 0 m/s, Find the speed of Larry and the skateboard after the "collision." Principle: Momentum is conserved in an inelastic collision.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter8: Momentum And Collisions
Section: Chapter Questions
Problem 49P
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![Solved Problem: Larry has a mass of 80 kg and runs across the front of the classroom with a speed of 4 m/s and jumps onto a giant skateboard.
The skateboard is initially at rest and a mass equal to Larry's. If friction with the floor is negligible, what is the speed of Larry and the
skateboard after he jumps on board?
Known: m = 80 kg, v₁ = 4 m/s, m₂ = 80 kg, v = 0 m/s, Find the speed of Larry and the skateboard after the "collision."
li
Principle: Momentum is conserved in an inelastic collision.
?
?
?
?
V2,=0
+X
V1, V2, V
+X
Since both Larry and the skateboard end up with the
same speed, set v
V for simplicity sake.
lf =2f
Ap=Pf-Pi = 0 → Pi = Pf
mvi+mv2i = mv₁f + mv2f
m₁v₁i + 0 = m₁V + m₂ V
m1 vli = (m₁ + m₂)V
V =
Complete the calculation to show that the common velocity V = V₁₁
Consider an extreme case for v₁ = 4 m/s and v₂ = 0 m/s: m, = 8000 kg, m, = 80 kg, find V.
Find V for another extreme case for v = 4 m/s and v₂ = 0 m/s: m₁ = 80 kg, m₂ = 8000 kg.
Consider the case for v₁ = 4 m/s and v₂=-2 m/s: m₁ = 80 kg, m, = 80 kg, find V.
m1
m₁+m₂
Vli
This relationship for the final shared velocity V only works
when the struck object, has an initial velocity which is zero.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a2bd348-d826-4056-b9ee-5fd404bc60f1%2F5a6a14b3-9c28-4745-9674-5f47d15f0d33%2Fyqsetvo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solved Problem: Larry has a mass of 80 kg and runs across the front of the classroom with a speed of 4 m/s and jumps onto a giant skateboard.
The skateboard is initially at rest and a mass equal to Larry's. If friction with the floor is negligible, what is the speed of Larry and the
skateboard after he jumps on board?
Known: m = 80 kg, v₁ = 4 m/s, m₂ = 80 kg, v = 0 m/s, Find the speed of Larry and the skateboard after the "collision."
li
Principle: Momentum is conserved in an inelastic collision.
?
?
?
?
V2,=0
+X
V1, V2, V
+X
Since both Larry and the skateboard end up with the
same speed, set v
V for simplicity sake.
lf =2f
Ap=Pf-Pi = 0 → Pi = Pf
mvi+mv2i = mv₁f + mv2f
m₁v₁i + 0 = m₁V + m₂ V
m1 vli = (m₁ + m₂)V
V =
Complete the calculation to show that the common velocity V = V₁₁
Consider an extreme case for v₁ = 4 m/s and v₂ = 0 m/s: m, = 8000 kg, m, = 80 kg, find V.
Find V for another extreme case for v = 4 m/s and v₂ = 0 m/s: m₁ = 80 kg, m₂ = 8000 kg.
Consider the case for v₁ = 4 m/s and v₂=-2 m/s: m₁ = 80 kg, m, = 80 kg, find V.
m1
m₁+m₂
Vli
This relationship for the final shared velocity V only works
when the struck object, has an initial velocity which is zero.
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