Starting from the fundamental thermodynamic equation, a) derive (OP) in terms of P, T, and V. b) derive (SP) for a vdW gas assuming that the compressibility factor is z = = 1+ = (b - 27) P PV RT RT RT c) calculate the enthalpy change (in J) for the isothermal increase in pressure from 3 atm to 15 atm of a mole of vdW gas at 25 °C. (a = 1.361 L² atm mol-2; b= 0.0318 L mol-¹)
Starting from the fundamental thermodynamic equation, a) derive (OP) in terms of P, T, and V. b) derive (SP) for a vdW gas assuming that the compressibility factor is z = = 1+ = (b - 27) P PV RT RT RT c) calculate the enthalpy change (in J) for the isothermal increase in pressure from 3 atm to 15 atm of a mole of vdW gas at 25 °C. (a = 1.361 L² atm mol-2; b= 0.0318 L mol-¹)
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.83E: Benzoic acid, C6H5COOH, is a common standard used in bomb calorimeters, which maintain a constant...
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![Starting from the fundamental thermodynamic
equation,
a) derive (OP) in terms of P, T, and V.
T
b) derive (o) for a vdW gas assuming that the
ӘР T
PV
compressibility factor is z = = 1+
+ P (b-a)
RT
RT
RT
c) calculate the enthalpy change (in J) for the
isothermal increase in pressure from 3 atm to 15
atm of a mole of vdW gas at 25 °C.
(a = 1.361 L² atm mol-2; b= 0.0318 L mol-¹)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2411fb4f-05b2-49fb-85fd-dfbead9ee29c%2F9fae6b1b-b8a3-4df2-9440-7092341d21f9%2Fenpmkv9_processed.png&w=3840&q=75)
Transcribed Image Text:Starting from the fundamental thermodynamic
equation,
a) derive (OP) in terms of P, T, and V.
T
b) derive (o) for a vdW gas assuming that the
ӘР T
PV
compressibility factor is z = = 1+
+ P (b-a)
RT
RT
RT
c) calculate the enthalpy change (in J) for the
isothermal increase in pressure from 3 atm to 15
atm of a mole of vdW gas at 25 °C.
(a = 1.361 L² atm mol-2; b= 0.0318 L mol-¹)
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