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Step 4 of 6 We now need the coordinates of a point on the tangent line. Find the y-coordinate of the point of tangency at x = 0 by evaluating y at x = 0. y(0) 18e0 cos(0) 18 Step 5 of 6 Recall the point-slope formula for the equation of a line given its slope m and a point (a, b) on the line. y-b=m m x-a a Step 6 of 6 Write the equation of the tangent line to y = 18e* cos(x) at x-coordinate 0 given that its slope is y'(0) = 18 and (0, 18) is a point on the line.

Step 4 of 6 We now need the coordinates of a point on the tangent line. Find the y-coordinate of the point of tangency at x = 0 by evaluating y at x = 0. y(0) 18e0 cos(0) 18 Step 5 of 6 Recall the point-slope formula for the equation of a line given its slope m and a point (a, b) on the line. y-b=m m x-a a Step 6 of 6 Write the equation of the tangent line to y = 18e* cos(x) at x-coordinate 0 given that its slope is y'(0) = 18 and (0, 18) is a point on the line.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.5: Trigonometric Graphs
Problem 29E
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Step 4 of 6 We now need the coordinates of a point on the tangent line. Find the y-coordinate of the point of tangency at x = 0 by evaluating y at x = 0. y(0) 18e⁰ cos(0) = 18 18 Step 5 of 6 Recall the point-slope formula for the equation of a line given its slope m and a point (a, b) on the line. y = b = m m x - a a Step 6 of 6 Write the equation of the tangent line to y = 18e* cos(x) at x-coordinate 0 given that its slope is y'(0) = 18 and (0, 18) is a point on the line.
Transcribed Image Text:Step 4 of 6 We now need the coordinates of a point on the tangent line. Find the y-coordinate of the point of tangency at x = 0 by evaluating y at x = 0. y(0) 18e⁰ cos(0) = 18 18 Step 5 of 6 Recall the point-slope formula for the equation of a line given its slope m and a point (a, b) on the line. y = b = m m x - a a Step 6 of 6 Write the equation of the tangent line to y = 18e* cos(x) at x-coordinate 0 given that its slope is y'(0) = 18 and (0, 18) is a point on the line.
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