RC =0.146k ohmXm =0.216k ohmRw = 2 ohmXL = 3.089 ohmCurrent IL = 15.16∠-4.38A VsIsRcRw JXL0002²=јХмIL=wwwA 140 / 32 V, 950 VA, 50 Hz single-phase transformer gave the following test results:Open circuit test on LV side: Ioc = 5.05 A, Poc = 134 WShort circuit test on HV side: Vsc:25 V, Psc 92 WA 22 load is connected to the LV side with rated voltage on the HV side.RL Supply CurrentCalculate the current drawn from the supply:ZmAIs=• Use Complex Numbers throughout.• Use Ohm's Law to get the loss currents in RC and XM.• Use Kirchhoff's Current Law to get the total current.

In this question we need to find the current drawn from the supply . Given: RC =0.146k ohm Xm…

Supply Current Calculate the current drawn from the supply: 2 mA Is = • Use Complex Numbers throughout. • Use Ohm's Law to get the loss currents in RC and XM. • Use Kirchhoff's Current Law to get the total current.

Supply Current Calculate the current drawn from the supply: 2 mA Is = • Use Complex Numbers throughout. • Use Ohm's Law to get the loss currents in RC and XM. • Use Kirchhoff's Current Law to get the total current.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.10P: A single-phase step-down transformer is rated 13MVA,66kV/11.5kV. With the 11.5 kV winding...

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Concept explainers

KVL and KCL

KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.

Sign Convention

Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.

Question

RC =0.146k ohm Xm =0.216k ohm Rw = 2 ohm XL = 3.089 ohm Current IL = 15.16∠-4.38A

Vs
Is
Rc
Rw JXL
0002²
=
јХм
IL
=
www
A 140 / 32 V, 950 VA, 50 Hz single-phase transformer gave the following test results:
Open circuit test on LV side: Ioc = 5.05 A, Poc = 134 W
Short circuit test on HV side: Vsc:
25 V, Psc 92 W
A 22 load is connected to the LV side with rated voltage on the HV side.
RL

Supply Current
Calculate the current drawn from the supply:
Z
mA
Is
=
• Use Complex Numbers throughout.
• Use Ohm's Law to get the loss currents in RC and XM.
• Use Kirchhoff's Current Law to get the total current.

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