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Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with ß = 0.5 and 6 = 3400. Determine the following in parts (a) and (b). P(X >3500) = a. b. P(X > 6000|X >3000) = c. Suppose that Xhas an exponential distribution with mean equal to 3400. Determine P(X 6000 X 3000) =

Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with ß = 0.5 and 6 = 3400. Determine the following in parts (a) and (b). P(X >3500) = a. b. P(X > 6000|X >3000) = c. Suppose that Xhas an exponential distribution with mean equal to 3400. Determine P(X 6000 X 3000) =

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.3: Special Probability Density Functions
Problem 36E
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Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with ß = 0.5 and 6 = 3400. Determine the following in parts (a) and (b). P(X >3500) = a. b. P(X > 6000|X >3000) = c. Suppose that Xhas an exponential distribution with mean equal to 3400. Determine P(X 6000 X 3000) =
Transcribed Image Text:Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with ß = 0.5 and 6 = 3400. Determine the following in parts (a) and (b). P(X >3500) = a. b. P(X > 6000|X >3000) = c. Suppose that Xhas an exponential distribution with mean equal to 3400. Determine P(X 6000 X 3000) =
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