Suppose the search field is V = 9 bytes long, the disk block size is B = 512 bytes, a record pointer Pr is 7 bytes, and a block pointer Pb is of 6 bytes. Each B-tree node can have at most p tree pointers, p- 1 data pointers and p - 1 search key field values. These must fit into a single disk block if each B-tree node is corresponds to a disk block. What is the average number of block pointers at 2d level of B-tree, given that B-tree is 69% full.
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- A JPJ department wants to maintain a database of up to 1800 license-plate numbers of people who receive frequent tickets so that it can be determined very quickly whether or not a given license plate is in the database. Speed of response is very important; efficient use of memory is also important, but not as important as speed of response. Which of the following data structures would be most appropriate for this task? A) a sorted linked list B) sorted array with 1800 entries hash table using open addressing with 1800 entries O D) a hash table using open addressing with 3600 entriesImplement M.A.S.H. Game Database (main.c)Use an array of DataNode pointers to store the game data, with an ENUM for the indexes as follows: database[HOME_LIST] ---->>>>> DataNode* listHead for list of homes database[FEMALE_SPOUSE_LIST] ---->>>>> DataNode* listHead for list of female spouses database[MALE_SPOUSE_LIST] ---->>>>> DataNode* listHead for list of male spouses database[OCCUPATION_LIST] ---->>>>> DataNode* listHead for list of occupations database[TRANSPORTATION_LIST] ---->>>>> DataNode* listHead for list of transportion - - methods database[HOMETOWN_LIST] ---->>>>> DataNode* listHead for list of hometowns The data values should be specified in an char array of strings by using an initializer list. This array will be passed to the BuildDataList function as a parameter which will in turn construct the list, allocating memory as required, and return a pointer to the listHead. This pointer…Analyze the given linked list figure, use the following pointers (head, p1, p2, p3, p4) and choose the correct answer: head 10 + 20 - 30 p1 data p2 tmp next p3• 20 p4 + NULL O p3->next is NULL O p3 is NULL O p3->next is equal to tmp O p3 is equal to p2
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- Using c language Implement M.A.S.H. Game Database (main.c)Use an array of DataNode pointers to store the game data, with an ENUM for the indexes as follows: database[HOME_LIST] ---->>>>> DataNode* listHead for list of homes database[FEMALE_SPOUSE_LIST] ---->>>>> DataNode* listHead for list of female spouses database[MALE_SPOUSE_LIST] ---->>>>> DataNode* listHead for list of male spouses database[OCCUPATION_LIST] ---->>>>> DataNode* listHead for list of occupations database[TRANSPORTATION_LIST] ---->>>>> DataNode* listHead for list of transportion - - methods database[HOMETOWN_LIST] ---->>>>> DataNode* listHead for list of hometowns The data values should be specified in an char array of strings by using an initializer list. This array will be passed to the BuildDataList function as a parameter which will in turn construct the list, allocating memory as required, and return a pointer to the…Suppose 1,000 Integer elements are generated at random and are inserted into a sorted linked list and a binary search tree (BST) separately. Considering the efficiency of searching for an element in the two structures, which of the following statements is true? The search operation on the list takes longer time because the numbers are not sorted. The search operation will take the same time in both structures. The search operation on the BST takes shorter time because it is relatively balanced. None of these. The search operation on the BST takes longer time because the numbers are not sorted.Analyze the given linked list figure, use the following pointers (head, p1, p2, p3, p4) and choose the correct answer describing the state of your data structure. head 10 20 30 p1 data p2 tmp next p3- 20 p4 NULL O p1 is equal to 5 O p1.data is equal to 5 O p1->data is equal to 5 O p1->next is equal to 5
- Use C++ Programming Language. Objective Define a circular buffer data structure and test it. Problem Description: A circular buffer (also called a circular queue) is circular list of nodes where data items are added on one end of the buffer and removed from the other end. Because the nodes form a circular list, the list has no end or beginning: the tail node points to the head node, creating a ring of nodes. You may think of the nodes as containers or slots that are all initially empty but can be assigned a value in their data field info. Every time a new data item is inserted (inserting to a buffer is often referred as Writing), one slot is filled and the buffer has one less empty slot. Every time a data item is removed (referred to as Reading), the buffer has one more empty slot. Since the list has no beginning and no end, a pointer (writeIndex) is used to mark the next empty slot to write to and a second pointer (readIndex) is used to mark the next node to read from. The…A linked list is a data structure made of a chain of objects called nodes. Each node contains at least two variables: a value and pointer. The value is the actual data within the Node as if it were an array element. The pointer, on the other hand, points to the next node in the chain. Unlike arrays, linked lists do not need to have a contiguous block of memory upon creation. This makes linked lists a lot more dynamic in size and in ease of insertion and deletion properties. Create an implementation of singly linked list using classes with minimum 5 nodes in Python with the following capabilities/functions: Traverse - print out all data from the linked list Insert - generate a node and attach to an existing linked list Search - find an item (data) from the linked list and return the node Remove - remove a node from the linked listI need to design, analyze, and implement algorithms to read in a sequence of characters from standard input and maintain the characters in a linked list with no duplicates. When read in a previously unseen character, insert it at the front of the list. When read in a duplicate character, delete it from the list and reinsert it at the beginning. The program implements the well-known move-to-front strategy which is useful for caching, data compression, and many other applications where items that have been recently accessed are more likely to be re-accessed. The program should read a sequence of characters and should insert unseen character at the front of the list. The program should check if the character is not in the list to be inserted at the front of the list. The program should delete a duplicate character and delete it from the list and insert it at the beginning of the list. The program should check if the character is already in the list and delete the character from the list…