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Target NO:(g) + H2(8) = NO(g) + H2O(g) Reaction A 2NO2(g) = 2NO(g) + O2(g) Ke = 1.45 x 10-6 at 500 K Reaction B ½H2O(g) ½H2(g) + ¼Oz(g) Ke = 1.43 x 10-12 at 500 K

Target NO:(g) + H2(8) = NO(g) + H2O(g) Reaction A 2NO2(g) = 2NO(g) + O2(g) Ke = 1.45 x 10-6 at 500 K Reaction B ½H2O(g) ½H2(g) + ¼Oz(g) Ke = 1.43 x 10-12 at 500 K

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.17P: 7-17 If a certain reaction takes 16 h to go to completion at 10°C, what temperature should we run it...
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What is the Kc for the Target reaction below at 500 K given Reaction A and B? (Picture) Explain how you got your answer.
Target NO:(g) + H2(g) = NO(g) + H20(g) Reaction A 2NO:(g) - 2NO(g) + O2(g) Ke = 1.45 x 10-6 at 500 K Reaction B ½H2O(g) = ½H¿(g) + ¼O2(g) Kc = 1.43 x 10-12 at 500 K
Transcribed Image Text:Target NO:(g) + H2(g) = NO(g) + H20(g) Reaction A 2NO:(g) - 2NO(g) + O2(g) Ke = 1.45 x 10-6 at 500 K Reaction B ½H2O(g) = ½H¿(g) + ¼O2(g) Kc = 1.43 x 10-12 at 500 K
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