The adsorption of a gas is described by the Langmuirisotherm with a= 1.85 kPa-1 at 25 oC. Calculate the pres-sure at which the fractional surface coverage is (a) 0.10 and (b) 0.90.
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The adsorption of a gas is described by the Langmuirisotherm with a= 1.85 kPa-1 at 25 oC. Calculate the pres-sure at which the fractional surface coverage is (a) 0.10 and (b) 0.90.
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- Suppose it is known that ozone adsorbs on a certain surface in accord with a Langmuir isotherm. How could you use the pressure dependence of the fractional coverage to distinguish between adsorption (i) without dissociation, (ii) with dissociation into O + O2, (c) with dissociation into O + O + O?The adsorption of a gas is described by the Langmuir isotherm with α = 0.548 kPa−1 at 25 °C. Calculate the pressure at which the fractional surface coverage is (i) 0.20, (ii) 0.75.In an experiment on the adsorption of oxygen on tungsten it was found that the same volume of oxygen was desorbed in 27 min at 1856 K and 2.0 min at 1978 K. What is the activation energy of desorption? How long would it take for the same amount to desorb at (i) 298 K, (ii) 3000 K?
- The adsorption of a certain substance, X, follows a Langmuir isotherm. Saturation coverage of the materials is 8 × 10-¹0 mol/cm² and 3 = 5 × 107 cm³/mol (assuming a₁ = C₁). At what concentration of X will the electrode surface be half covered (i.e., = 0.5)? Sketch the adsorption isotherm of the substance.The following data were obtained for the adsorption of a certain material (ORA) on activated carbon at 25 °C. Sample Activated carbon mass (g) 1.0119 [ORA) initial (M) [ORA] at equilibrium (М) 0.0044 number 0.0096 1.0186 1.0360 0.0289 0.0207 3 0.0578 0.0446 0.0721 0.1002 4 1.0129 0.0867 1.0393 0.1156 1.0312 1.0198 0.1445 0.1926 0.2407 0.2889 0.1270 7 1.0270 1.0252 0.1742 0.2227 0.1108 8 1. Try fitting these data using Langmuir Isotherm and obtain K and monolayer of ORA molecules per one gram 3. Which isotherm describe best the adsorption of ORA on activated carbon and why? 4. If a monolayer of N2 molecules is 0.03075 mole per one gram of activated carbon, and the surface area on one N2 molecules is 0.162 nm, determine: a. surface area per one gram of activated carbon b. surface area of one ORA molecule1.2-MIB (Methylisoborneol) is one of the by-products of algae and is a representative trace pollutant that causes taste and smell of water. The isothermal adsorption equation of 2-MIB applied with activated carbon in water without organic matter was experimentally determined as follows.q = 1.48C^(0.65) Where q is ng 2-MIB / g activated carbon and C is the concentration of g / L 2-MIB (g / L).(n is 10 ^ -9) A. Calculate the amount of activated carbon (mg / L) required to reduce the concentration of 2-MIB to 5 g / L. It is assumed that the concentration of 2-MIB in water without organic matter is 50 g / L.B. The activated carbon adsorption column will be designed with a three-year operating period. If the density of activated carbon is 540 kg / m3 and the design flow rate per column effective cross-section is 10 m / hr, find the depth of activated carbon in the empty bed contact time (EBCT) and column. Here, it is assumed that there is no competitive adsorption that can interfere with…
- In a study of the gas phase decomposition of hydrogen iodide at 700 K HI(g)V½ H2(g) + ½ I½(g) the concentration of HI was followed as a function of time. It was found that a graph of 1/[HI] versus time in seconds gave a straight line with a slope of 1.72×103 M1s1and a y-intercept of 0.667 M1. Based on this plot, the reaction is order in HI and the rate constant for the reaction is M1s1The following data were obtained for the adsorption of a certain material (ORA) on activated carbon at 25 °C. Sample number [ORA) initial (M) [ORA] at equilibrium Activated carbon mass (М) (g) 1.0119 0.0096 0.0044 2 1.0186 1.0360 0.0289 0.0578 0.0207 0.0446 3 4 1.0129 0.0867 0.0721 1.0393 1.0312 1.0198 1.0270 1.0252 0.1002 0.1156 0.1445 0.1270 0.1742 0.2227 7 0.1926 8 0.2407 0.2889 0.1108 4. If a monolayer of N2 molecules is 0.03075 mole per one gram of activated carbon, and the surface area on one N2 molecules is 0.162 nm, determine: a. surface area per one gram of activated carbon b. surface area of one ORA moleculeHydrogen purification was conducted at 550 °C using a 3-mm-thick palladium sheet having an area of 0.25 m?. (a) Calculate the diffusion coefficient of hydrogen in palladium at this temperature. The preexponent and the activation energy are 12,000 J/mol and 6.5 x 108 m?/s, respectively. R = 8.3145 J/mol-K. (b) When the steady-state condition was attained, hydrogen concentrations at the high- and low-pressures side of the plate were 1.7 and 0.5 kg/m³. Compute the amount of hydrogen that passes through the sheet per hour (in kg/h).
- а. Identify THREE (3) isotherm shapes that are typically encountered in an adsorption process for a single adsorbate and illustrate the behavior through equilibrium relations.The following data were obtained for the adsorption of a certain material (ORA) on activated carbon at 25 °C. Activated carbon mass (g) 1.0119 [ORA) initial (M) [ORA] at equilibrium (М) Sample number 1 0.0096 0.0044 1.0186 0.0289 0.0207 3 1.0360 0.0578 0.0446 4 1.0129 0.0867 0.0721 5 1.0393 0.1156 0.1002 6. 1.0312 0.1445 0.1270 7 1.0198 0.1926 0.1742 0.2227 1.0270 0.2407 1.0252 0.2889 0.1108 1. Try fitting these data using Langmuir Isotherm and obtain K and monolayer of ORA molecules per one gram 2. Try fitting these data using Freundlich Isotherm and obtain its constants 3. Which isotherm describe best the adsorption of ORA on activated carbon and why? 4. If a monolayer of N2 molecules is 0.03075 mole per one gram of activated carbon, and the surface area on one N2 molecules is 0.162 nm, determine: a. surface area per one gram of activated carbon b. surface area of one ORA moleculeFor the adsorption of a substance A from aqueous solution by charcoal at 25C, the Freundlich constants are n = 3.0 and k = 0.50 for y in grams per gram and C in g L-1. What weight of A will be adsorbed by 2 g of charcoal from 1 L of a solution containing originally 2 g of substance? Answer is [1 g]