The analysis of the contents of Car 53 is as follows: %C = 65.60 %H = 9.44 MS Data: 128 (100%), 129 (7.8%) Proton NMR: 0.90 (3H, t), 1.19 (2H, m6), 1.47 (2H, m5), 3.97 (2H, t), 5.83 (1H, d), 6.12 (1H, dd), 6.41 (1H, ^ d) What is the MF? C7H1202 (no spaces, example, for water = H2O) What is the IUPAC name?

The analysis of the contents of Car 53 is as follows: %C = 65.60 %H = 9.44 MS Data: 128 (100%), 129 (7.8%) Proton NMR: 0.90 (3H, t), 1.19 (2H, m6), 1.47 (2H, m5), 3.97 (2H, t), 5.83 (1H, d), 6.12 (1H, dd), 6.41 (1H, ^ d) What is the MF? C7H1202 (no spaces, example, for water = H2O) What is the IUPAC name?

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter22: Reactions Of Benzene And Its Derivatives

Section: Chapter Questions

Problem 22.10P: Addition of m-xylene to the strongly acidic solvent HF/SbF5 at 45C gives a new species, which shows...

See similar textbooks

Similar questions

Identify the reagent used in the following transformation: OH P Q HO OH HO (A) P = LIAIH, Q = KMNO4 Q = MnO, / CH,Cl, Q= Ag,CO, on celite, PhH %3D (В) P= NABH, /MeOH %3D (C) P=CeCl,.7H,O (D) P= NABH, /CeCl,.7H,0 , / CeCl,.7H,O Q = MnO, / CH,Cl,
18. Proton NMR spectra are given together with molecular formula. Propose a structure that corresponds to each spectrum. (Hint: Find IHD first). Assign peaks to show which protons give rise to which peaks 10 10 10 (b) C4H8O₂ Offset: 2.4 ppm (b) C₂H100 9 (c) CsHgO₂ 9 8 8 7 7 6 6 6 5 8 (ppm) OHz 5 8 (ppm) 4 3.08 2.98 2.88 2.78 8 (ppm) 50Hz 4 4 3 2 1 0 0
Elucidate the structure using the 1H and 13C NMR data.
9 C 2 H, d 2 H, d 8 6 Solution Process: 5 PPM 4 3 H, s 3 3 H, s 2 1 Analysis compound C: Structure of C (paste in chemdraw): 09 Proton NMR: report in this format shift (splitting, integration); e.g., 3.20 (t, 2H) alevlan (webmerlo ni eresa) O to entou de (naiisipeni pritiige) Hirle temot air ni noger:AMM motors com-Ingh ari tot poitilga ni 10123 stol
The Mass spec of the compound has a molecular ion peak at m/z = 178 and a base peak at m/z = 178 (yes, the same value). The proton NMR showed the following: Signal Shift (ppm) Integration 8.4 8.0 7.4 A B C There are four C-13 signals: 125, 126, 128, and 132 ppm. A simple C13 chart is provided at the The integrations for the four C13 peaks are 2:2:1:2 respectively. The IR Spectrum is presented below (black vertical line at 3000 cm³¹ was drawn in): INFRARED SPECTRUM 0.8 0.6 0.4 Splitting Singlet 1 Doublet 2 Doublet of Doublets 2 C. 2000 Wavenumber (cm-1) Other information available: The molecule does not react with bromine in chloroform but can be brominated using bromine and FeBr3, and three different monobromo products are obtained. a. The number of H's in the compound have to be a multiple of what integer? Explain your answer. b. The number of C's in the compound have to be a multiple of what integer? is the maximum number of C's that can be in the compound? determined the maximum…
The partial ¹H NMR spectrum for ester A is as below. 10 На H₂ 9 Ha OCH 3 5 (i) (ii) (iii) Name the splitting pattern for Ha. Give the approximate chemical shifts for protons H₁, H₂ and Hc. Explain the difference in chemical shift for H₂ and Hc.
Draw the structure of the compound identified by the simulated 'H NMR and C NMR spectra. The molecular formula of the compound is C,0H,O. 12 (Blue numbers next to the lines in the 'H NMR spectra indicate the integration values.) H NMR 1H 2H 2H 2H 2H|| 3H 10 8. 4 (dd) g 13C NMR 220 200 180 160 140 120 100 80 60 40 20 8 (ppm) Deduce the structure from the spectra. Select Draw Rings More Erase
Indicate two basic differences that exist between the spectra of 1H y 13C in NMR.
1H NMR Spectroscopy Spectra run at 60 MHz 70 SPECI 4 50 30 20 Explain the main features of the 1 H NMR spectrum of crotonic acid (4), Spec. 4. Deduce the stereochemistry of the carboxylic acid (CO2H peak not shown).
Treatment of 2-methylpropanenitrile [(CH3)2CHCN] withCH3CH2CH2MgBr, followed by aqueous acid, affords compound V, whichhas molecular formula C7H14O. V has a strong absorption in its IRspectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91(triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and2.60 (septet, 1 H) ppm. What is the structure of V?
Following are 'H-NMR and 1BC-NMR spectral data for compound F (C,,H,0). From chis information, deduce the structure of compound F. 'H-NMR 13C-NMR 0.83 (d, 6H) 207.82 50.88 2.11 (m, 1H) 134.24 50.57 2.30 (d, 2H) 129.36 24.43 3.64 (s, 2H) 128.60 22.48 7.2-7.4 (m, 5H) 126.86
Analysis of a sweet-smelling, neutral compound of carbon, hydrogen and oxygen produced the following results: %C = 54.5; %H = 9.1. From its mass spectrum, the molecular ion had a mass/charge ratio of 88. Its infra-red spectrum showed a prominent peak at 1735 cm–1. Figure below shows the NMR spectrum of the compound. Which of the following is this compound? A. 3-hydroxybutanalB. Methyl propionateC. Ethyl acetateD. 2-methylpropanoic acidE. Methoxyacetone