The data below are for water (H₂O) Melting Boiling Heat of point Point Fusion Heat of Vaporization SH Capacity (liquid) SH Capacity (vapor) 2260 J/g 4.18 J/g °C 1.90 J/gºC 1. Draw a heating curve for substance water, going from -20°C to 125°C on the axis below. Write in all formulas used to calculate heat. 25°C 100°C- 0.0°C 100.0°C Temp- OC- F E 334 J/g Nq=MAHFUS EmSSAT с SH Capacity (solid) 2.05 J/gºC q=m4Hvap q=mSLAT B q=mSVAT OMSAT Gheat m=mas AT (T2-T)-Char ir Te S-specific hea 9mAHfusion- mHvaporization -20°C- Time b. Determine the amount of heat necessary to convert 15.0g of water at 100.0°C to steam at 100.0°C. G=m4Hvaporization Hvaporization=2260)/9 9=159×22601/9 9-33900) AH 2260/9 AH c. Determine the amount of heat necessary to convert 15.0g of ice at 0.0°C to liquid at 0.0° C. q-159x 334 9=159x2260 4-50105 All-33439 AH vaporization=2260 J/g d. Determine the amount of heat given off when 25g of water cools from 56.2°C to 33.5°C. 25x4-18x(-22.7) = -2372.15) 9=2.315 -2372.15)=-94.9)/8 25g e. Determine the amount of heat needed to raise the temperature of 19.6g of X from -15°C to 2.0°C ΔΗ AH = -94.93/g

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Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 85QAP: On a hot day, you take a six-pack ot a on a pcmc, cooling it with ice. Each empty (aluminum) can...
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The data below are for water (H₂O)
Boiling
Point
Heat of
SH Capacity
(solid)
SH Capacity
(liquid)
SH Capacity
(vapor)
Vaporization
334 J/g
2260 J/g
2.05 J/gºC
4.18 J/g °C
1.90 J/gºC
1. Draw a heating curve for substance water, going from -20°C to 125°C on the axis below.
Write in all formulas used to calculate heat.
125°C
Melting
point
0.0°C
100°C-
OC
100.0°C
Temp->
F
E
Heat of
Fusion
q=MAHFU
EmSs4T
q=m4Hvap
q=mSLAT
q=mSVAT
B
OMSAT
19=heat
m=mass
AT=(T₂-T)-Change
-20°C-
Time
b. Determine the amount of heat necessary to convert 15.0g of water at 100.0°C to steam at 100.0°C.
G=m4Hvaporization
Hvaporization=2260)/g
-33900)
9
AH 2260/9
q=
S-specific heat
9=159x22601/9
c. Determine the amount of heat necessary to convert 15.0g of ice at 0.0°C to liquid at 0.0° C.
9-15gx334
9=159x2260
AH =
9-mAhfusion-melting
mAltraporization boiling
4-50105
All-384 3g
ΔΗ
AH vaporization=2260/g
d. Determine the amount of heat given off when 25g of water cools from 56.2°C to 33.5°C.
25x4-18x(-22.7) = -2372.15)
-2372.15)=-94.9)/8
25g
e. Determine the amount of heat needed to raise the temperature of 19.6g of X from -15°C to 2.0°C
9=2.3kg
411--94.93/9
ΔΗ =
Temp
18
Transcribed Image Text:The data below are for water (H₂O) Boiling Point Heat of SH Capacity (solid) SH Capacity (liquid) SH Capacity (vapor) Vaporization 334 J/g 2260 J/g 2.05 J/gºC 4.18 J/g °C 1.90 J/gºC 1. Draw a heating curve for substance water, going from -20°C to 125°C on the axis below. Write in all formulas used to calculate heat. 125°C Melting point 0.0°C 100°C- OC 100.0°C Temp-> F E Heat of Fusion q=MAHFU EmSs4T q=m4Hvap q=mSLAT q=mSVAT B OMSAT 19=heat m=mass AT=(T₂-T)-Change -20°C- Time b. Determine the amount of heat necessary to convert 15.0g of water at 100.0°C to steam at 100.0°C. G=m4Hvaporization Hvaporization=2260)/g -33900) 9 AH 2260/9 q= S-specific heat 9=159x22601/9 c. Determine the amount of heat necessary to convert 15.0g of ice at 0.0°C to liquid at 0.0° C. 9-15gx334 9=159x2260 AH = 9-mAhfusion-melting mAltraporization boiling 4-50105 All-384 3g ΔΗ AH vaporization=2260/g d. Determine the amount of heat given off when 25g of water cools from 56.2°C to 33.5°C. 25x4-18x(-22.7) = -2372.15) -2372.15)=-94.9)/8 25g e. Determine the amount of heat needed to raise the temperature of 19.6g of X from -15°C to 2.0°C 9=2.3kg 411--94.93/9 ΔΗ = Temp 18
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