The electromagnet shown in Fig. P3.7 can be used to lift a sheet of steel. The coil has 400 turns and a resistance of 5 ohms. The reluctance of the magnetic material is negligible. The magnetic core has a square cross section of 5 cm by 5 cm. When the sheet of steel is fitted to the electro- magnet, air gaps, each of length g = 1 mm, separate them. An average force of 550 newtons is required to lift the sheet of steel. (a) For de supply, (i) Determine the dc source voltage. (ii) Determine the energy stored in the magnetic field. (b) For ac supply at 60 Hz, determine the ac source voltage.

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The electromagnet shown in Fig. P3.7 can be used to lift a sheet of steel. The coil has 400 turns
and a resistance of 5 ohms. The reluctance of the magnetic material is negligible. The magnetic
core has a square cross section of 5 cm by 5 cm. When the sheet of steel is fitted to the electro-
magnet, air gaps, each of length g 1 mm, separate them. An average force of 550 newtons is
required to lift the sheet of steel.
(a) For dc supply,
(i) Determine the dc source voltage.
(ii) Determine the energy stored in the magnetic field.
(b) For ac supply at 60 Hz, determine the ac source voltage.
q+
R
g
Transcribed Image Text:The electromagnet shown in Fig. P3.7 can be used to lift a sheet of steel. The coil has 400 turns and a resistance of 5 ohms. The reluctance of the magnetic material is negligible. The magnetic core has a square cross section of 5 cm by 5 cm. When the sheet of steel is fitted to the electro- magnet, air gaps, each of length g 1 mm, separate them. An average force of 550 newtons is required to lift the sheet of steel. (a) For dc supply, (i) Determine the dc source voltage. (ii) Determine the energy stored in the magnetic field. (b) For ac supply at 60 Hz, determine the ac source voltage. q+ R g
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