The following data pertain to an investment proposal: Cost of investment Annual cost savings Estimated salvage value Expected life of investment $45,000 $10,000 $0 5 years 10% Discount rate What is the present value of the proposed investment?
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- Refer to the following data for a proposal: Investment Php cost 585,528 Expected life 5 years Php 56,254 Salvage value Php Annual 329,902 receipts Php Annual |192,804 expenses 15% MARR What is annual worth of the project?The following data pertain to an investment proposal (Ignore income taxes.): Cost of the investment Annual cost savings $ 35,000 $ 12,000 $ 6,000 Estimated salvage value Life of the project Discount rate. Click here to view Exhibit 14B-1 and Exhibit 14B-2, to determine the appropriate discount factor(s) using the tables provided. The net present value of the proposed investment is closest to: 5 years 18%: According to the data given in the table below and to the annual equivalent expenditure method, which project should be preferred? Cash flows Project A Project B Project C Investment Amount (TL) 1500000 3475000 5900000 Operating expense (TL / year) Salvage Value (TL) Economic life of the project (years) Discount rate (%) 750000 500000 300000 250000 150000 100000 20 18 15 20 18 15
- The following information is available for a potential investment for Panda Company: $110000 Initial investment Net annual cash inflow Net present value Salvage value Useful life 20000 O 5.50. O 2.49. O 3.55. O 1.40. 44150 10000 10 years The potential investment's profitability index isNet Present Value Method, Internal Rate of Return Method, and Analysis for a Service Company The management of Advanced Alternative Power Inc. is considering two capital investment projects. The estimated net cash flows from each project are as follows: Biofuel Equipment Year 1 2 3 4 Year 1 2 The wind turbines require an investment of $513,900, while the biofuel equipment requires an investment of $1,093,320. No residual value is expected from either project. Present Value of an Annuity of $1 at Compound Interest 12% 0.893 1.690 2.402 3.037 3.605 3 4 5 Wind Turbines 6 7 8 9 10 Required: $180,000 180,000 180,000 180,000 6% 0.943 1.833 2.673 3.465 4.212 4.917 5.582 6.210 6.802 7.360 10% 0.909 1.736 2.487 3.170 3.791 4.355 4.868 5.335 $360,000 360,000 360,000 360,000 5.759 6.145 4.111 4.564 4.968 5.328 5.650 15% 0.870 1.626 2.283 2.855 3.353 3.785 4.160 4.487 4.772 5.019 20% 0.833 1.528 2.106 2.589 2.991 3.326 3.605 3.837 4.031 4.192 1a. Compute the net present value for each project. Use…The following information Company: available for a potential investment for Rose Initial investment P80,000 Net annual cash inflow 20,000 Net present value 36,224 Salvage value 10,000 Useful life 10 yrs. The potential investment's profitability index is A. 2.50 B. 2.85 C. 4.00 D. 1.45
- The following data pertain to an investment proposal (Ignore income taxes.): Cost of the investment $ 52,000 Annual cost savings $ 16,000 Estimated salvage value $ 8,000 Life of the project 5 years Discount rate 13 % Click here to view Exhibit 13B-1 and Exhibit 13B-2, to determine the appropriate discount factor(s) using the tables provided. The net present value of the proposed investment is closest to: (Round your intermediate calculations and final answer to the nearest whole dollar amount.)From the given values below, which machine should be selected using (a) Present worth Method and (b) Future worth Method if interest rate is 10% per year? Machine A B Initial Cost (Php) Annual Operating Cost 146,000 15,000 80,000 10,000 3 220,000 10,000 75,000 25,000 Annual Revenue Salvage Value Useful Life (years) 6Given the following data of equipment A and B. A First Cost P 50 000 P 150 000 2000 Salvage Value Annual Maintenance 6000 Economic life 6000 3000 5 15 The MARR is 12%. Use sinking fund depreciation. What is the rate of return for the additional initial investment on equipment B?
- Given the following table for two alternatives. consider that the interest rate = 10% Alternative A B First cost, $ -90,000 -750,000 AOC, $/year -50,000 -10,000 Salvage value, $ Life, years 8,000 2,000,000 00 All of the following equations for calculating the capitalized cost of alternative B are correct, except: Select one: = -750,000 – 10,000/0.10 a. + 2,000,000/(1+0.10) b. = [-750,000(0.10) – 10,000]/0.10 c. capitalized cost = -750,000 – 10,000/0.10 + 2000000 (0.10) d. capitalized cost = -750,000 – 10,000/0.10Given the financial data for four mutually exclusive alternatives in the table below, determine the best alternative using the incremental rate of return (AROR) analysis. MARR = 10%. A B C D $15,000 $21,200 $36,000 45,000 1,600 700 400 1,000 First cost O &M Cost/ year Benefit/year 8,000 9,000 13,000 Salvage value 3,000 4,600 6,000 Life in years 4 15,000 10,000Harris Corporation has provided the following data concerning an investment project that it is considering: Initial investment Annual cash flow Salvage value at the end of the project Expected life of the project Discount rate $ 160,000 $ 54,000 $ 11,000 O $67,000 O $160,516 O $516 O $(5,776) 4 15 per year years % Use Exhibit 7B-1 and Exhibit 7B-2, to determine the appropriate discount factor(s) using the tables provided. The net present value of the project is closest to: