२चपThe following divider is used to divide 8ten by 2ten:DivisorShift right64 bitsQuotient64-bit ALUShift left32 bitsRemainderControlWritetest64 bitsFor simplicity, use 4 bits for theotient and 8 bits for both divisor and remainder.What will be the initial values of quotient, divisor and remainder?1000, 0010 0010, 0000 0000a)0000, 0010 0000, 0000 1000b)c)0010, 0000 0000, 0000 1000d)0000, 0000 0010, 0000 1000e)0000, 0010 0000, 1000 0000f)0000, 1000 0000, 0010 0000g)0000, 0000 1000, 0000 0010h)None of the aboveWhat will be the values of quotient, divisor and remainder after the fourth iteration of the division algorithm?(after iteration 4)a)0000, 0000 0010, 0000 0010b)0001, 0010 0000, 0000 00000100, 0000 0100, 0000 0100c)0010, 0000 0010, 0000 0000d)e)0000, 00000001, 0000 0000f)0001, 0000 0010, 0010 0000g)0010, 0000 0100, 0000 0000h)None of the above

The following divider is used to divide 8ee by 2gen Diviser Shit right 64 bits Quotient 64-bil ALU Shit left 32 bits Remainder Control test Write 64 bits For simplicity, use 4 bits for the quotient and 8 bits for both divisor and remainder. What will be the initial values of quotient, divisor and remainder? a) 1000, 0010 0010, 0000 0000 0000, 0010 0000, 0000 1000 0010, 0000 0000, 0000 1000 b) d) 0000, 0000 0010, 0000 1000 e) 0000, 0010 0000, 1000 0000 0000, 1000 0000, 0010 0000 0000, 0000 1000, 0000 0010 h) None of the above What will be the values of quotient, divisor and remainder after the fourth iteration of the division algorithmlafter iteration 4) a) 0000, 0000 0010,0000 0010 b) 0001. 0010 0000, 0000 0000 0100, 0000 0100, 0000 0100 d) 0010, 0000 0010, 0000 0000 0000, 0000 0001.0000 0000 e) 1) 0001. 0000 0010, 0010 0000

The following divider is used to divide 8ee by 2gen Diviser Shit right 64 bits Quotient 64-bil ALU Shit left 32 bits Remainder Control test Write 64 bits For simplicity, use 4 bits for the quotient and 8 bits for both divisor and remainder. What will be the initial values of quotient, divisor and remainder? a) 1000, 0010 0010, 0000 0000 0000, 0010 0000, 0000 1000 0010, 0000 0000, 0000 1000 b) d) 0000, 0000 0010, 0000 1000 e) 0000, 0010 0000, 1000 0000 0000, 1000 0000, 0010 0000 0000, 0000 1000, 0000 0010 h) None of the above What will be the values of quotient, divisor and remainder after the fourth iteration of the division algorithmlafter iteration 4) a) 0000, 0000 0010,0000 0010 b) 0001. 0010 0000, 0000 0000 0100, 0000 0100, 0000 0100 d) 0010, 0000 0010, 0000 0000 0000, 0000 0001.0000 0000 e) 1) 0001. 0000 0010, 0010 0000

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter8: Arrays And Strings

Section: Chapter Questions

Problem 21PE

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