The following molarities were calculated from replicate standardization of a solution: 0.5025, 0.5012, 0.5012, 0.5028, 0.5023, 0.5015, and 0.5039 M. Assuming no determinate errors, what is the upper limit of the 95% confidence interval?
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- The following molarities were calculated from replicate standardization of a solution: 0.5021, 0.5015, 0.5035, 0.5007, 0.504, 0.5025, and 0.5008 M. Assuming no determinate errors, what is the upper limit of the 95% confidence interval?The following molarities were calculated from replicate standardization of a solution: 0.5022, 0.5022, 0.5021, 0.5008, upper limit of the 95% confidence interval?A volumetric calcium analysis on triplicate samples of the blood serum of a patient believed to be suffering from a hyperparathyroid condition produced the following data: mmol Ca/L = 3.15, 3.25, 3.26. What is the 95% confidence interval for the mean of the data, assuming no prior information about the precision of the analysis?
- The percentage of an additive in gasoline was measured six times with the following results: 0.13; 0.12; 0.16; 0.17; 0.20 and 0.11%. What is the 99% confidence interval for the additive percentage?A new procedure for the rapid determination of sulphur in kerosene was tested on a sample known from its method of preparation to contain 0.123% S (µ = 0.123% S). The results for % S were 0.112, 0.118, 0.115, and 0.119. Determine whether the data indicate that there is a bias in the method at the 95% confidence levelIn a survey of 1000 large corporations, 250 said that, given a choice between a job candidate who smokes and an equally qualified nonsmoker, the nonsmoker would get the job (USA Today).(a) Let p represent the proportion of all corporations preferring a nonsmoking candidate. Find a point estimate for p.(b) Find a 0.95 confidence interval for p.(c) As a news writer, how would you report the survey results regarding the proportion of corporations that hire the equally qualified nonsmoker? What is the margin of error based on a 95% confidence interval?
- Chemistry In an analysis of the content of carbohydrate present in a glycoprotein, the following results were found: 12.6, 11.9, 13.0, 12.7 and 12.5 g of carbohydrate per 100 g of protein. Taking into account that σ is unknown, the confidence interval for the average value at a 90% confidence level of the carbohydrate content is: Select one:to. 12.5 ± 0.4b. 12.5 ± 0.2c. 12.5 ± 0.5d. 12.5 ± 0.37) The homogeneity of the chloride level in a water sample from a lake was tested by an analyst. Below are the concentration in parts per million (ppm) of Cl: 27.32, 27.22, 27.21, 27.24, 27.20 i. Determine the mean and median. ii. Calculate the confidence limit at 90%. iii. Identify a possible outlier and use the Q-test to determine whether it can be retained or rejected at 90% confidence levelThe organic base, tris-(hydroxymethyl)aminomethane (or simply TRIS or THAM) is an excellent primary standard. A 0.2486 g sample of the primary standard grad TRIS, (CH2OH)3CNH2 (M.M. = 121.14) was dissolved in distilled water and required 24.88 mL of a hydrochloric acid solution. Calculate the molarity of the solution
- A clinical chemist obtained the following data for the alcohol content of a sample of blood: % C,H OH: o.084, 0.089, and o.079. Calculate the 95% confi- dence interval for the mean assuming that (a) the three results obtained are the only indication of the precision of the method and that (b), from previousMganga is doing a routine analysis in a copper plating factory. He is regularly making up solutions of verypure CuSO4.5H2O. He suspect that a batch of a reagent used to make up a stock solution of CuSO4.5H2Ois impure and it may contains some CuCl2. He asked you to determine the percentage impurity as follows:Dissolve1.500g of a mixture and make up to 1.00L mark.150mL of this solution was treated with 20.00mLof 0.100M AgNO3 to remove 98.6% of chloride as AgCl precipitate.