The following results were obtained from a disk diffusion test for a strain of Escherichia coli. Chemotherapeutic Zone of inhibition (mm) A 7 B 10 C 18 D 3 Which drug above (A, B, C, or D) is most effective against this E. coli strain?
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Gene Interactions
When the expression of a single trait is influenced by two or more different non-allelic genes, it is termed as genetic interaction. According to Mendel's law of inheritance, each gene functions in its own way and does not depend on the function of another gene, i.e., a single gene controls each of seven characteristics considered, but the complex contribution of many different genes determine many traits of an organism.
Gene Expression
Gene expression is a process by which the instructions present in deoxyribonucleic acid (DNA) are converted into useful molecules such as proteins, and functional messenger ribonucleic (mRNA) molecules in the case of non-protein-coding genes.
The following results were obtained from a disk diffusion test for a strain of Escherichia coli.
Chemotherapeutic |
Zone of inhibition (mm) |
A |
7 |
B |
10 |
C |
18 |
D |
3 |
Which drug above (A, B, C, or D) is most effective against this E. coli strain?
***Which drug above (A, B, C, or D) is most effective against Staphylococcus aureus? Explain your answer.
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- Nitrate reduction test can be used to differentiate between Pseudomonads and Enterobacteriaceae. You inoculated your Nitrate broth with your unknown; after incubation, you added 5 drops of reagent A and 5 drops of reagent B. You observe a red color within 2 minutes. Is this a + or a - reaction? Assuming you did not get a red color, you then added a pinch of Zinc and this time tou obtained a red color. What does this mean?What will be the results of the following experiment with explanations: A. Gram-positive bacteria and Gram-negative bacteria were placed into 0.2% NaCl solution. B. Gram-negative bacterial isolate was placed into 0. 3% NaCl solution containing only Lysozyme enzyme. C. Gram-positive bacteria and Gram-negative bacteria were placed into 0.09% NaCl solution containing only Penicillin?12:28 TABLE 1 Disk Symbol A B Today 10:42 AM INTERPRETING INHIBITION ZONES OF TEST CULTURES CHEMICAL METHODS OF CONTROL: ANTIMICROBIAL DRUGS Antimicrobial Agent Ampicillin when testing gram-negative bacteria Ampicillin when testing gram-positive bacteria Chloramphenicol Ceftazidime Carbenicillin Carbenicillin when testing Pseudomonas Cephalothin Ciprofloxacin Erythromycin Cefoxitin Sulfisoxazole Bunnsoxazo Gentamicin Conca companion Imipenem Penicillin when testing staphylococci Penicillin when testing other bacteria Polymyxin Rifampin Streptomycin Trimethoprim- Sulfamethoxazole (TMP-SMZ) Tetracycline Vancomycin when testing Staphylococcus spp. Vancomycin when testing enterococci PROCEDURE Second Period 1. Measure the zones of inhibition in millimeters, using a ruler on the underside of the plate (see Figure 3b). If the diameter is difficult to measure, measure the radius from the center of the disk to the edge of the zone. Multiply the radius by 2 to get the diameter of the zone. Disk…
- One of the early results shows that the post-centrifugation pellet of encapsulated cells also contains EA1 and/or Sap. Why is this not proof that Bacillus anthracis cells have both an S-layer and a capsule simultaneously? I need help finding the answer in the article and explain in short answer link to article: https://www.ncbi.nlm.nih.gov/pmc/articles/PMC106848/You have isolated a beta-lactamase producing Staphylococcus aureus (not a MRSA strain) from an infected surgical site on your patient. If for genetic reasons, your patient is allergic to all antibiotics except beta-lactam antibiotics such as ampicillin ( they can only take Beta-lactam antibiotics such as ampicillin), which strategy below could you use to treat this Staphylococcus aureus infection in your patient? Note different answers compared to previous question. give the patient erythromycin can use a beta-lactamse resistant beta-lactam such as methicillin or oxacillin O give the patient penicillin give the patient an azole drugIf you have 4 compounds and you test them for antimicrobial activity using a disk diffusion assay and one is very active, one is moderately active, one is slightly active and one is not active at all, draw the disk, the zone of inhibition that you would see and a pretend numerical value to indicate the size of the zone in mm, give each one a number 1 – 4 and rank them from most effective to least effective as an antimicrobial.
- After testing the potency of different β-lactamase inhibitors against purified OXA-M290 enzyme, the antimicrobial activity of combinations of β-lactam antibiotics and β-lactamase inhibitors is tested against the E. coli KGH1 strain that produces OXA-M290. The results of these studies can be used to identify the best antibiotic to treat an infection caused by this E. coli strain. Broth microdilution tests are carried out with a panel of β-lactam antibiotics and β-lactamase inhibitors to determine their MICs against E. coli KGH1. These tests are carried out in a 96-well microplate. Three β-lactam antibiotics (amoxicillin, ceftazidime, and ertapenem) and three β-lactamase inhibitors (sulbactam, tazobactam, and vaborbactam) are tested. The rows in the microplate correspond to the following antibiotics and inhibitors: Row A: amoxicillinRow B: amoxicillin + sulbactamRow C: ceftazidimeRow D: ceftazidime + sulbactamRow E: ertapenemRow F: ertapenem + sulbactamRow G: ertapenem + tazobactamRow H:…A relatively large zone of inhibition surrounding an antimicrobial disk on a Kirby-Bauer test plate would most likely be interpreted as: a. sensitive reaction b. intermediate reaction c. resistant reactionResults of Kirby Bauer test on E. Coli with penicilin , ampicilin, tetracycline, chloramphenicol disks showed zero zone of inhibition while there were zones around all these disks on S. aureus this should be interpreted as this drug is narrow spectrum a) True b) False
- A culture of S. cerevisea has an overnight OD of 2.3 (1.0 OD is approx 1.0x107 cells/ml) You will be plating 100µl onto agar and want the final count of colonies on the plate to be around 300 colonies. How much of the 2.3 OD culture must you use to get a 500µl subdilution (with sterile water), so that you have diluted enough to get approx 300 colonies per 100ulIn the Avery, McLeod, McCarty Experiment where supernatant from heat killed, virulent S Strain pneumonia solutions were added to non-virulent R Strain pneumonia cell cultures and allowed to grow in liquid media (i.e., broth). In tubes where Protease was added to the supernatant prior to cell culture, what was the observed effect when plating and growing the S. pneumonia cells to solid media? Selected answer will be automatically saved. For keyboard navigation, press up/down arrow keys to select an answer. a b C d e All RNA was degraded and Transformation of the R Strain to S Strain occurred. All Protein was degraded and Transformation of the R Strain to S Strain occurred. All DNA was degraded and Transformation of the R Strain to S Strain occurred. All RNA was degraded and no Transformation occurred indicating RNA is the molecule of Transformation inheritance None of the above are trueAntibiotic Code Zone of Inhibition (mm) S, I, or R? Penicillin P 15 Streptomycin S 8 Ampicillin A 25 Chloramphenicol C 14 Bacitracin B 5 QUESTIONS: Which antimicrobial agent was most effective against your organism? Can you determine from your results whether this antimicrobial agent will also be most effective against another bacterium? Why or why not? Is this technique measuring bacteriostatic effect, bactericidal effects, or both? Explain. 4) Consider the following list of hypothetical antibiotics, tested against Escherichia coli in a Kirby-Bauer test: Antibiotic Zone of Inhibition (mm) Astonostatin 12 Bodaciosporin 25 Crazifloxacin 5 Dorkimycin 16 When the above antibiotics were tested as treatments for E. coli infections in humans, it was found that Dorkimycin has virtually no effect on the infection, while Astonostatin is the most effective of the four antibiotics listed. Propose an explanation for this result. Based purely on these…