The internal auditing staff of a local manufacturing company performs a sample audit each quarter to estimate the proportion of accounts that are delinquent (more than 90 days overdue). For this quarter, the auditing staff randomly selected 400 customer accounts and found that 80 of these accounts were delinquent. What is the margin of error for a 95 percent confidence interval for the proportion of all delinquent customer accounts at this company?

Q: If a retailer would like to estimate the proportion of their customers who bought an item after…

A: Given data,     P=58%=0.58     E=7%=0.07     z-value at 95% confidence is  zc =1.98     n=?

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: In this question, It has been given that Margin of error = 0.05 and level of significance = 0.005.…

Q: The confidence interval was (41%, 45%) What was the margin of error? +/- % What was the summary…

A:

Q: 5.From a sample of 1,000 college students, 28% watch the Super Bowl game each year. Find the margin…

A:

Q: An environmental science teacher at a high school with a large population of students wanted to…

A: The 95% confidence interval for the proportion of all students at the school who would respond yes…

Q: In a random sample of 100 voters in a school district, 40 of them stated they were in favor of the…

A: Solution: Let X be the number of voters stated they were in favor of the school district bond…

Q: In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find…

A: Obtain the 90% confidence interval for the true proportion of accidents that occurred at work. The…

Q: n a survey of 500 students, 180 students said that they prefer classes on Mondays and Wednesdays…

A:

Q: In order to estimate the proportion of entering students who graduate within six years, the…

A: Solution: Let X be the number of students who graduate within six years and n be the sample number…

Q: In a recent survey of 200 households, 172 had central air conditioning.  Find the 85% confidence…

A: Given that In a recent survey of 200 households, 172 had central air conditioning That is…

Q: how many people should you sample? 4 80 125 382 383

A: Given : Margin of error: ME = 0.05

Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

A:

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A:

Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: The random variable cyber bullied follows normal distribution. The sample size is 14795. The number…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A:

Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: We have given that,  Favorable cases (X) = 2219 and sample size   (n) = 14795. Then,  We will find…

Q: In a survey with human resources managers, 71% of respondents thought they should hire new staff…

A: Given information: Denote the population proportion of all respondents who thought that they should…

Q: A political candidate has asked you to conduct a poll to determine what percentage of people support…

A: Solution:There is no estimates available, hence the sample proportion is assumed to be 0.50.The…

Q: In a recent poll, 150 people were asked if they liked dogs, and 55% said they did. Find the margin…

A:

Q: What is the margin of error for a 90% confidence interval?

A: It is given that Sample size n = 850 Number of residents support property tax, X = 410 The critical…

Q: The following table shows the results of a survey in which 1017 adults from the United States, 1060…

A: (1)

Q: A researcher asks 600 people if they received a flu vaccine, and 65% said they did. What is the 95%…

A: From the provided information Sample size (n) = 600 65% said they received a flu vaccine that is…

Q: In a recent poll, 260 people were asked if they liked dogs, and 67% said they did. Find the margin…

A: Given: p = 67%=0.67 n= 260 The value of z at a 90% confidence level is 1.645, which can be found by…

Q: According to a poll taken in a certain​ country, when adults were asked whether they were​ thriving,…

A: Given,n = 440x = 193a) Sample proportion p^ = xn    p^ = 193440 = 0.4386 b)np^ = 440 x 0.4386 =…

Q: in a random sample of 192 college students, 129 had part-time jobs. Find the margin of error for the…

A:

Q: A regional survey of 561 companies asked the vice president of operations how satisfied he or she was…

A:

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: n our Condor Cafe, the Oxnard College Culinary Program offers the most delicious and affordable…

A: Given that, n=255,x=75

Q: In a random sample of 200 people, 154 said they watched educational television. We wish to construct…

A: Given there are 200 people, 154 said they watched educational television. a) Given confidence…

Q: An environmental science teacher at a high school with a large population of students wanted to…

A: Question : (b) Given the method used by the environmental science teacher to collect the responses,…

Q: n 2013, the Gallup poll asked 1,039 American adults if they believe there was a conspiracy in the…

A: Given data, n=1039 x=634 sample proportion p=x/n =634/1039 =0.61   z-value at 90% confidence is…

Q: In a survey on downloading music, a poll asked 714 Internet users if they "ever downloaded music…

A:

Q: A random sample of accountants were asked whether they double-check their calculations on a tax…

A: Here the sample proportion is given by, p^ Therefore α level confidence interval is given by, p^ -…

Q: In a recent poll, 110 people were asked if they liked dogs, and 40% said they did. Find the margin…

A: For 99% confidence intervalα=1-CI=1-0.99=0.01So, zα2=z0.012=z0.005=2.576

Q: Suppose you are designing a survey of firework plans among Kansas residents. You would like for the…

A: Here we need to find the required sample size with a 95% confidence level to estimate the number of…

Q: Which of the below is the correct calculation of the 95¥% confidence interval?

A: Given that sample size n = 670 And sample proportion = 0.85 The critical value of Z at 95%…

Q: Suppose you want to construct an 80% confidence interval for the proportion of businesses that…

A: Given:Margin of Error (E)=3.5%=0.035   For Confidence level 80%, the significance level (α) is…

Q: For the same sample statistics, which level of confidence would produce the widest confidence…

A:

Q: Wildlife biologists inspect 200 deer taken by hunters and find 45 of them carrying Lyme disease…

A: Given; x=45n=200Then the sample proportion is given by;p^=45200=0.225The level of significance…

Q: In a recent poll, 410 people were asked if they liked dogs, and 44% said they did. Find the margin…

A: n = 410 p^=0.44 Confidence interval = 95%

Q: The owner of the Gas station wishes to determine the proportion of customers who use credit card. he…

A:

Q: A recent survey of 1,000 people found that 90% of Americans support background checks for purchasing…

A:

Q: An airline transports over 10 000 passengers daily, and the airline is curious what proportion of…

A: Critical value: Using Excel formula "=NORM.S.INV(1-(0.1/2))", the z-value is obtained as 1.645.

Q: confidence interval for the true proportion

A: We have to find out the confidence interval for the true proportion.

Q: Aston’s Career Service wants to find out what proportion of Aston’s students work in a part-time…

A: From the given information, Population proportion = p = 60% = 0.60 Margin of error = E = 4% = 0.04…

Q: It was found that in a sample of 90 teenage boys, 70% of them have received speeding tickets. What…

A: Given data ,n=90P=70%=0.7The z-value at 90% confidence is1.645=z∝12=1.645

Q: In a study by Sallie Mae and Gallup, 323 of the 569respondents said that they paid for their…

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.