the lead in an aqueous lead(II) nitrate solution can be precipitated out by adding potassium iodide. if we have 490.7 mL of 0.774 M lead (II) nitrate solution how much 2.05 M potassium iodide must we add to exactly precipitate all the lead (II) ions? give answer in mL and round to the correct number of sig figs
the lead in an aqueous lead(II) nitrate solution can be precipitated out by adding potassium iodide. if we have 490.7 mL of 0.774 M lead (II) nitrate solution how much 2.05 M potassium iodide must we add to exactly precipitate all the lead (II) ions? give answer in mL and round to the correct number of sig figs
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.151QP: A 10.0-mL sample of potassium iodide solution was analyzed by adding an excess of silver nitrate...
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the lead in an aqueous lead(II) nitrate solution can be precipitated out by adding potassium iodide. if we have 490.7 mL of 0.774 M lead (II) nitrate solution how much 2.05 M potassium iodide must we add to exactly precipitate all the lead (II) ions? give answer in mL and round to the correct number of sig figs
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