The motion of a point on the circumference of a rolling wheel of radius 3 feet is described by the vector function F(t) = 3(22t – sin(22t))i + 3(1 – cos(22t)) Find the velocity vector of the point. v(t) =| (66– 66 cos ( 22t) ) i + 66 sin( 22t ) j Find the acceleration vector of the point. a(t) = Find the speed of the point. s(t) = 66y cos( 22t) + sin(22t ) ×

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Additional Topics In Trigonometry
Section3.3: Vectors In The Plane
Problem 10ECP
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The motion of a point on the circumference of a rolling wheel of radius 3 feet is described by the vector
function
7(t) = 3(22t – sin(22t))i + 3(1 – cos(22t))}
Find the velocity vector of the point.
v(t) =
(66 – 66 cos(22t) )i + 66 sin( 22t)jv
Find the acceleration vector of the point.
a(t) =
Find the speed of the point.
s(t) =
66y cos( 22t) + sin( 22t) x
Transcribed Image Text:The motion of a point on the circumference of a rolling wheel of radius 3 feet is described by the vector function 7(t) = 3(22t – sin(22t))i + 3(1 – cos(22t))} Find the velocity vector of the point. v(t) = (66 – 66 cos(22t) )i + 66 sin( 22t)jv Find the acceleration vector of the point. a(t) = Find the speed of the point. s(t) = 66y cos( 22t) + sin( 22t) x
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