Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
The number of atoms diffusing through a membrane with an area of 4 cm is 6.16×10³ atoms/sec (based on the definition of flux =M/A.t). Concentration gradient (Ac/ A x) for diffusing atoms with D=9×10- 12 cm²/sec becomes. Note: J = –D(Ac/ A x) -1.71×1023 -1.71×1024 -1.71×1022 -1.71×1024

The number of atoms diffusing through a membrane with an area of 4 cm is 6.16×10³ atoms/sec (based on the definition of flux =M/A.t). Concentration gradient (Ac/ A x) for diffusing atoms with D=9×10- 12 cm²/sec becomes. Note: J = –D(Ac/ A x) -1.71×1023 -1.71×1024 -1.71×1022 -1.71×1024

icon
Related questions
Question
The number of atoms diffusing through a membrane with an area of 4 cm? is 6.16×1013 atoms/sec (based on the definition of flux =M/A.t). Concentration gradient (Ac/ A x) for diffusing atoms with D=9×10- 12 cm?/sec becomes. Note: J = - D(Ac/ A x) -1.71×1023 -1.71×1024 -1.71×1022 -1.71×1024
Transcribed Image Text:The number of atoms diffusing through a membrane with an area of 4 cm? is 6.16×1013 atoms/sec (based on the definition of flux =M/A.t). Concentration gradient (Ac/ A x) for diffusing atoms with D=9×10- 12 cm?/sec becomes. Note: J = - D(Ac/ A x) -1.71×1023 -1.71×1024 -1.71×1022 -1.71×1024
Expert Solution
steps

Step by step

Solved in 3 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer