The velocity of a particle moving in the x-y plane is given by (3.70i + 7.44j) m/s at time t = 6.60 s. Its average acceleration during the next 0.024 s is (6.71 + 2.8j) m/s². Determine the velocity v of the particle at t = 6.624 s and the angle between the average-acceleration vector and the velocity vector at t = 6.624 s. Answers: v = (i 10.4 i + i 10.24 j) m/s 0= i 21.87 O
The velocity of a particle moving in the x-y plane is given by (3.70i + 7.44j) m/s at time t = 6.60 s. Its average acceleration during the next 0.024 s is (6.71 + 2.8j) m/s². Determine the velocity v of the particle at t = 6.624 s and the angle between the average-acceleration vector and the velocity vector at t = 6.624 s. Answers: v = (i 10.4 i + i 10.24 j) m/s 0= i 21.87 O
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Transcribed Image Text:The velocity of a particle moving in the x-y plane is given by (3.70i + 7.44j) m/s at time t = 6.60 s. Its
average acceleration during the next 0.024 s is (6.7i+ 2.8j) m/s2. Determine the velocity v of the particle
at t = 6.624 s and the angle between the average-acceleration vector and the velocity vector at t =
6.624 s.
Answers:
v=i 10.4
10.24
j) m/s
8=
i 21.87
+
IN
i
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