The vertical distance between eye level and the ground for a certain swimmer, who is standing upright, is 1.55 m. If the swimmer is standing 2.00 m from the edge of a 2.50-m-deep swimming pool, how far from the base of the pool will the swimmer be able to see a coin that is at the bottom of the pool? The swimmer is represented by the upward directed arrow in the diagram, and the distance between the base of the pool and the coin is “d”. The index of refraction of water is 1.33. a. 1.55 m b. 0.950 m c. 1.85 m d. 2.15 m e. 1.25 m

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Chapter25: Geometric Optics
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Problem 22PE: An optical fiber uses flint glass clad with crown glass. What is the critical angle?
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The vertical distance between eye level and the ground for a certain swimmer, who is standing upright, is 1.55 m. If the swimmer is standing 2.00 m from the edge of a 2.50-m-deep swimming pool, how far from the base of the pool will the swimmer be able to see a coin that is at the bottom of the pool? The swimmer is represented by the upward directed arrow in the diagram, and the distance between the base of the pool and the coin is “d”. The index of refraction of water is 1.33.

 

a.

1.55 m

  b.

0.950 m

  c.

1.85 m

  d.

2.15 m

  e.

1.25 m

Eye Level
1.55 m
0,
2.00 m
Water
02
2.50 m
Coin
d
Transcribed Image Text:Eye Level 1.55 m 0, 2.00 m Water 02 2.50 m Coin d
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