Then, for testing the iodide test, the acidified solution of sodium iodide (NaI) reacts with Fe(NO3)3 , the following reaction takes place and showed FeI3 and NaNO3 are formed as products. The formed FeI3 is dark yellow to brown in colour. 3NaI + Fe(NO3)3 → FeI3 + 3NaNO3 After the addition of dichloro-methane the colour still remains the same. The equation is as follows: 2FeI3 + 3CH2Cl2 → 3CH2I2 + 2FeCl3 All the above reactions involved in the test are double displacement reactions. So, the above test is positive (formation of dark yellow to brown color solution), it indicates the presence of iodide ion in the solution. Question : Explain more about this experiment results.
Then, for testing the iodide test, the acidified solution of sodium iodide (NaI) reacts with Fe(NO3)3 , the following reaction takes place and showed FeI3 and NaNO3 are formed as products. The formed FeI3 is dark yellow to brown in colour. 3NaI + Fe(NO3)3 → FeI3 + 3NaNO3 After the addition of dichloro-methane the colour still remains the same. The equation is as follows: 2FeI3 + 3CH2Cl2 → 3CH2I2 + 2FeCl3 All the above reactions involved in the test are double displacement reactions. So, the above test is positive (formation of dark yellow to brown color solution), it indicates the presence of iodide ion in the solution. Question : Explain more about this experiment results.
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter19: Transition Metals And Coordination Chemistry
Section: Chapter Questions
Problem 21E: Predict the products of each of the following reactions and then balance the chemical equations. (a)...
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Then, for testing the iodide test, the acidified solution of sodium iodide (NaI) reacts with Fe(NO3)3 , the following reaction takes place and showed FeI3 and NaNO3 are formed as products. The formed FeI3 is dark yellow to brown in colour.
3NaI + Fe(NO3)3 → FeI3 + 3NaNO3
After the addition of dichloro-methane the colour still remains the same. The equation is as follows:
2FeI3 + 3CH2Cl2 → 3CH2I2 + 2FeCl3
All the above reactions involved in the test are double displacement reactions. So, the above test is positive (formation of dark yellow to brown color solution), it indicates the presence of iodide ion in the solution.
Question : Explain more about this experiment results.
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