Theorem: Product Rule If f(x) = F(x)S(x) is the product of differentiable functions, then f'(x) = S(x)F'(x) F(x)S' (x) [S(x)]² O f'(x) = F(x)S' (x) + S(x)F' (x) O f'(x) = F'(x)S' (x) + S(x)F(x) O f'(x) = F(x)S' (x) – S(x)F" (x) O f'(x) = F'[S(x)]S'(x) O f'(x) = F'(x)S" (x)

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.CR: Chapter 9 Review
Problem 54CR
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Theorem: Product Rule
If f(x) = F(x)S(x) is the product of differentiable functions, then
f'(x) =
S(x)F'(x) F(x)S' (x)
[S(x)]²
O f'(x) = F(x)S' (x) + S(x)F' (x)
O f'(x) = F'(x)S' (x) + S(x)F(x)
○ f'(x) = F(x)S" (x) – S(x)F' (x)
-
○ f'(x) = F'[S(x)]S′(x)
O f'(x) = F'(x)S" (x)
Transcribed Image Text:Theorem: Product Rule If f(x) = F(x)S(x) is the product of differentiable functions, then f'(x) = S(x)F'(x) F(x)S' (x) [S(x)]² O f'(x) = F(x)S' (x) + S(x)F' (x) O f'(x) = F'(x)S' (x) + S(x)F(x) ○ f'(x) = F(x)S" (x) – S(x)F' (x) - ○ f'(x) = F'[S(x)]S′(x) O f'(x) = F'(x)S" (x)
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