Three forces, FA, FB, and FC, intersect at the origin. Only 2 of these forces are shown on the diagram. Find the magnitude of FC and its direction coordinate angles for equilibrium, given:FA = 825 N, α = 150 °, β = 75 °FB = 600 N, θ = 20 °, Φ = 30 ° Answers The magnitude of FC is: FC = 798 N FC = 455 N FC = 331 N FC = 308 N FC = 522 N The direction coordinates angles of FC are:αC αC=69.1 ° αC=60.2 ° αC=40.7 ° αC=106 ° αC=43.8 ° βC βC=101 ° βC=262 ° βC=149 ° βC=171 ° βC=109 ° γC γC=65.3 ° γC=70.3 ° γC=111 ° γC=96.7 ° γC=1.70E2 ° FBThree forces, FA. FB. and Fc. intersect at the origin. Only 2 of these forces are shown on the diagram. Find the magnitude of Fc and itsdirection coordinate angles for equilibrium, given:FA = 825 N, a = 150 °, B= 75Fe = 600 N, 0= 20°, = 30 °

Answered: Image /qna-images/answer/77cc552d-eb0a-4a3a-aa23-881bb62a0736.jpg

Three forces, FA, FB, and FC, intersect at the origin. Only 2 of these forces are shown on the diagram. Find the magnitude of FC and its direction coordinate angles for equilibrium, given: FA = 825 N, α = 150 °, β = 75 ° FB = 600 N, θ = 20 °, Φ = 30 °

Three forces, FA, FB, and FC, intersect at the origin. Only 2 of these forces are shown on the diagram. Find the magnitude of FC and its direction coordinate angles for equilibrium, given: FA = 825 N, α = 150 °, β = 75 ° FB = 600 N, θ = 20 °, Φ = 30 °

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter10: Virtual Work And Potential Energy

Section: Chapter Questions

Problem 10.33P

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Chemical and Phase Equilibrium

Phase diagrams or equilibrium phase diagrams are the graphical representations that show the phase transformations of the constituting elements with respect to the pressure, temperature, and compositions. The diagrams show the conditions that limit the different phases, namely solid, liquid, and gas. The diagram can also be utilized to verify the relations between the state variables. Most of the phase diagrams are temperature-pressure phase diagrams, with the variable parameter as the composition. Usually other variables such as solubility and pressure parameters are not indicated in the phase diagram. For a one-component system (unary phase diagram), the phase diagram is generally a function of temperature and pressure as the state variables, or temperature and volume. However, for a binary system (two-phase) having two components, the phase diagram is a function of temperature and composition as the state variables only. Coexisting of the different phases of the constituting elements is indicated in the phase diagram. A ternary phase diagram can be characterized by consisting of three phases in equilibrium.

Question

Three forces, FA, FB, and FC, intersect at the origin. Only 2 of these forces are shown on the diagram. Find the magnitude of FC and its direction coordinate angles for equilibrium, given:
FA = 825 N, α = 150 °, β = 75 °
FB = 600 N, θ = 20 °, Φ = 30 °

Answers

The magnitude of F_C is:

		F_C = 798 N
		F_C = 455 N
		F_C = 331 N
		F_C = 308 N
		F_C = 522 N

The direction coordinates angles of F_C are:

α_C

		α_C=69.1 °
		α_C=60.2 °
		α_C=40.7 °
		α_C=106 °
		α_C=43.8 °

β_C

		β_C=101 °
		β_C=262 °
		β_C=149 °
		β_C=171 °
		β_C=109 °

γ_C

		γ_C=65.3 °
		γ_C=70.3 °
		γ_C=111 °
		γ_C=96.7 °
		γ_C=1.70E2 °

FB
Three forces, FA. FB. and Fc. intersect at the origin. Only 2 of these forces are shown on the diagram. Find the magnitude of Fc and its
direction coordinate angles for equilibrium, given:
FA = 825 N, a = 150 °, B= 75
Fe = 600 N, 0= 20°, = 30 °

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