Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Two nitro (N0,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of ɛ, where 8=1.0 x 10 -24 J. In other words, each NO, group could have ɛ of rotational kinetic energy, or 2ɛ, or 3ɛ, and so forth – but it cannot have just any old amount of rotational kinetic energy. Two rotating NO, groups Suppose the total rotational kinetic energy in this system is initially known to be 41ɛ. Then, some heat is removed from the bonded to a surface. system, and the total rotational kinetic energy falls to 30ɛ. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.

Two nitro (N0,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of ɛ, where 8=1.0 x 10 -24 J. In other words, each NO, group could have ɛ of rotational kinetic energy, or 2ɛ, or 3ɛ, and so forth – but it cannot have just any old amount of rotational kinetic energy. Two rotating NO, groups Suppose the total rotational kinetic energy in this system is initially known to be 41ɛ. Then, some heat is removed from the bonded to a surface. system, and the total rotational kinetic energy falls to 30ɛ. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.130QP
See similar textbooks
icon
Related questions
icon
Concept explainers
Question
Two nitro (NO,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of ɛ, where 8= 1.0 x 10 -24 J. In other words, each NO, group could have ɛ of rotational kinetic energy, or 2ɛ, or 3ɛ, and so forth - but it cannot have just any old amount of rotational kinetic energy. Two rotating N0, groups Suppose the total rotational kinetic energy in this system is initially known to be 41ɛ. Then, some heat is removed from the bonded to a surface. system, and the total rotational kinetic energy falls to 30ɛ. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol. Check 2021 McGraw-Hill Education All Rights Reserved Tems of Uhe Privacy Accesbil Explanation MacBook Air olo
Transcribed Image Text:Two nitro (NO,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of ɛ, where 8= 1.0 x 10 -24 J. In other words, each NO, group could have ɛ of rotational kinetic energy, or 2ɛ, or 3ɛ, and so forth - but it cannot have just any old amount of rotational kinetic energy. Two rotating N0, groups Suppose the total rotational kinetic energy in this system is initially known to be 41ɛ. Then, some heat is removed from the bonded to a surface. system, and the total rotational kinetic energy falls to 30ɛ. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol. Check 2021 McGraw-Hill Education All Rights Reserved Tems of Uhe Privacy Accesbil Explanation MacBook Air olo
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Molecular Motion in Gases
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
General Chemistry - Standalone book (MindTap Cour…
General Chemistry - Standalone book (MindTap Cour…
Chemistry
ISBN:
9781305580343
Author:
Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
Chemistry
ISBN:
9781337399425
Author:
Steven S. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS