we had given key value pairs make map and print whole map in java | 1 mango 2 apple 3 orange 4 0 pineapple banand we had given key value pairs make map and print whole map in java1 mango3 2 apple13 orange5.4 pineapple6 5 banana7.

BASICS` Create object of map Map<key,value> map = new HashMap<key,value>(); and by put…

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we had given key value pairs make map and print whole map in java 2 1 mango 3 2 apple 3 orange 5 4 pineapple 5 banana

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write an explanation for each line. Explain the logic. What will be displayed andwhy? .model small.stack 100h.386.codemain procmov cl, 7CHmov bl, 2SHL BL,1l:call kdec bljnz lMOV DL, 0AHcall dELMOV DL, 44Hcall dELMOV DL, 4FHcall dELMOV DL, 4EHcall dELMOV DL, 45Hcall dELmov ax, 4c00hint 21hk procm:mov ah, 1int 21hcmp al, CL jnz msub cl,2retk endpdEL procmov ah,6 int 21hretdEL endpmain endpend main
Do you reach many, do you reach one? def knight_jump(knight, start, end): An ordinary chess knight on a two-dimensional board of squares can make an “L-move” into up to eight possible neighbours. However, we can generalize the entire chessboard into k dimensions from just the puny two. A natural extension of the knight's move to keep moves symmetric with respect to these dimensions is to define the possible moves as some k-tuple of strictly decreasing nonnegative integer offsets. Each one of these k offsets must be used for exactly one dimension of your choice during the move, either as a positive or a negative version.For example, the three-dimensional (4,3,1)-knight makes its way by first moving four steps along any one of the three dimensions, then three steps along any other dimension, and then one step along the remaining dimension, whichever dimensions that was. These steps are considered to be performed together as a single jump that does not visit or is blocked by any of the…
Try in. Omega go.
Do you reach many, do you reach one? def knight_jump(knight, start, end): An ordinary chess knight on a two-dimensional board of squares can make an “L-move” into up toneight possible neighbours. However, we can generalize the entire chessboard into k dimensions from just the puny two. A natural extension of the knight's move to keep moves symmetric with respect to these dimensions is to define the possible moves as some k-tuple of strictly decreasing nonnegative integer offsets. Each one of these k offsets must be used for exactly one dimension of your choice during the move, either as a positive or a negative version. For example, the three-dimensional (4,3,1)-knight makes its way by first moving four steps along any one of the three dimensions, then three steps along any other dimension, and then one step along the remaining dimension, whichever dimensions that was. These steps are considered to be performed together as a single jump that does not visit or is blocked by any of the…
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In Java code: In Java code: In a game of Tic Tac Toe, two players take turns making an available cell in a 3 x 3 grid with their respective tokens (either X or O). When one player has placed three tokens in a horizontal, vertical, or diagonal row on the grid, the game is over and that player has won. A stalemate occurs when all the cells on the grid have been filled with tokens and neither player has achieved a win. Code a program that emulates a Tic Tac Toe game. When you are done, a typical session will look like this: Welcome to tic-tac-toe. Enter coordinates for your move following the X and O prompts. 1 2 3A | | -----B | | -----C | |X:A2 1 2 3A |X| -----B | | -----C | |O:B3 1 2 3A |X| -----B | |O -----C | | And so on. Illegal moves will prompt the user again for a new move. A win or a stalemate will be announced, mentioning the winning side if any. The program will terminate whenever a single game is complete. For this lab, you will be…
Solve using JAVA only Given a square chess board of size N, solve the N queens problem. Print out the number of solutions for a given N. You do not need to print out or produce the actual solutions, only the number of correct solutions. Solve for N between 2 and 8. Try your program with 9 and 10, produce those results if it returns in a reasonable amount of time. The N queens problem is to find every configuration of N queens distributed on an NxN square chess board such that all queens are safe from attack by each other.
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Using the graph in the question: Write Java code to create an Adjacency Matrix M to represent the graph. Write Java code to create an Adjacency List L to represent the graph.
can you help me to draw the flow chart for the java code: import java.util.Scanner;class BinoNode {int data;int numNodes;BinoNode arr[];public BinoNode(int k) {data = -1;numNodes = k;arr = new BinoNode[numNodes];}}class BinomialTree {private BinoNode root; private int order, size;public BinomialTree(int k) {size = 0;order = k;root = new BinoNode(order);createTree(root);}private void createTree(BinoNode r) {int n = r.numNodes;if (n == 0) {return;}for (int i = 0; i < n; i++) {r.arr[i] = new BinoNode(i);createTree(r.arr[i]);}}public void clear() {size = 0;root = new BinoNode(order);createTree(root);}public void insert(int val) {try {insert(root, val);} catch (Exception e) {}}private void insert(BinoNode r, int val) throws Exception {if (r.data == -1) {r.data = val;size++;throw new Exception("inserted !");}int n = r.numNodes;for (int i = 0; i < n; i++) {insert(r.arr[i], val);}}public void printTree() {System.out.print("\nBinomial Tree =…
Programming in Java. What would the difference be in the node classes for a singly linked list, doubly linked list, and a circular linked list? I attached the node classes I have for single and double, but I feel like I do not change enough? Also, I use identical classes for singular and circular node which does not feel right. Any help would be appreciated.