We have found the following Maclaurin series. x4n 142n (2n)! Now we can use this to find the Maclaurin series of the given function, treating the term 13x as a constant and using the rule can = cªn. f(x) = 13x cos 05 (1141+²2) cos(4x²) = (-1)^- n = 0 = 13x ‹ Ë (−1)”. n = 0 = - Σ n = 0 (-1)". x4n 142n (2n)! 4n+1 142 (2n)! X

We have found the following Maclaurin series. x4n 142n (2n)! Now we can use this to find the Maclaurin series of the given function, treating the term 13x as a constant and using the rule can = cªn. f(x) = 13x cos 05 (1141+²2) cos(4x²) = (-1)^- n = 0 = 13x ‹ Ë (−1)”. n = 0 = - Σ n = 0 (-1)". x4n 142n (2n)! 4n+1 142 (2n)! X

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.3: Geometric Sequences

Problem 49E

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